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Directrix
 2 years ago
Best ResponseYou've already chosen the best response.0Let x = y. Then, x  y + y = y (x  y + y) / ( x  y) = y / ( x  y) 1 + y / ( x  y ) = y / ( x  y) Therefore, 1 = 0

saloniiigupta95
 2 years ago
Best ResponseYou've already chosen the best response.1I hope I can reply :) Here in the first step you took x=y... If you take this into consideration, you cannot do the third step... that is , dividing both sides by (xy) because in doing so , you are actually dividing by 0 on both sides which is absurd... or in mathematical sense, undefined...

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.0yes logic @wio and as @saloniiigupta95 says dividing by zero is against the law @Directrix

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1\[0\implies 1\]is true.

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1Considering you meant 0 and 1 as in the boolean values.

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.0yeah howcome false implies true?

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1Because of the identity:\[\phi \implies \psi \ \ \cancel{\equiv} \ \ \psi \implies \phi \ \ \ \ \rm if \ \ \ \ \ \phi \cancel{\equiv} \psi \]

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1I mean \(\phi \implies \psi \equiv \neg(\psi \implies \phi) \ \ \ \ \rm if \ \ \ \ \phi \equiv \neg \psi \)

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.0\[\underline{\qquad\phi\implies\psi\\ {\large\land}\quad\phi\iff\neg\psi\\}\]\[\therefore\quad \neg(\psi\implies\phi)\] ?

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1I have problems with the notation :P

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.0my problem is \[0\to0\to0\to\dots\to0\to0\to1\to1\to\dots\to1\to1\to1\]

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1In any order, it'd be \(1\).

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.0i can see why zero implies zero , , i can see one implies one, but why/when does zero imply one ?

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1\( \ \ \rm m \implies 1 \ \ \ \) is always true.
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