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JenniferSmart1

  • 3 years ago

\[tan^{-1}(tan\frac{4*\pi}{5})=\]

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  1. JenniferSmart1
    • 3 years ago
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    I get \[\frac\pi{5}\]

  2. JenniferSmart1
    • 3 years ago
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    what did I do wrong?

  3. hartnn
    • 3 years ago
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    its -pi/5 , right ? \(\tan (\theta - \pi)=\tan \theta\) 4pi/5 - pi = -pi/5 also, \(\tan^{-1}\tan \theta = \theta \)

  4. JenniferSmart1
    • 3 years ago
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    oh it's period is pi.....I see

  5. hartnn
    • 3 years ago
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    yes, period of tan theta = pi. thats why its has same values after every 180 degrees...

  6. JenniferSmart1
    • 3 years ago
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    makes sense. Thanks!

  7. hartnn
    • 3 years ago
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    welcome :)

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