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Whatever1
 2 years ago
what is y' in Arc csc squaroot of 2x
Whatever1
 2 years ago
what is y' in Arc csc squaroot of 2x

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satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0\[y=\csc^{1}(\sqrt{2x})\]?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0if i recall correctly the derivative of \(\csc^{1}(x)\) is \(\frac{1}{x\sqrt{x^21}}\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0so you want \(\frac{d}{dx}[\csc^{1}(\sqrt{2x})]\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0what you need is the derivative of \(\csc^{1}(x)\) and the chain rule

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{d}{dx}[\csc^{1}(x)=\frac{1}{x\sqrt{x^21}}\] i know because i just looked it up replace \(x\) by \(\sqrt{2x}\) and then multiply by the derivative of \(\sqrt{2x}\) which is \(\frac{1}{\sqrt{2x}}\) then probably some algebra to clean it up
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