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gjhfdfg

  • 3 years ago

Plotting complex numbers?

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  1. gjhfdfg
    • 3 years ago
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    Ive got , \[-5\sqrt{3} - \]

  2. Tom-Todd
    • 3 years ago
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    Plot them on an argand diagram, where the Y axis is in terms of i

  3. gjhfdfg
    • 3 years ago
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    I meant \[-5 \sqrt{3} -5i\] How do I plot the sqrt 3?

  4. Tom-Todd
    • 3 years ago
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    One sec, I got to look something up

  5. Tom-Todd
    • 3 years ago
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    so, -5(root)3 would be your x coordinate then -5i would be your y

  6. Tom-Todd
    • 3 years ago
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    I guess you just have to work out roughly where -5(root)3 would be on your x axis

  7. Tom-Todd
    • 3 years ago
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    it's going to be at about -8.5

  8. gjhfdfg
    • 3 years ago
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    Alright, & -5i means its gonna be on the y axis right?

  9. Tom-Todd
    • 3 years ago
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    Yeah, -5i is on the y axis, however, the Y acis on an argand diagram is actually in terms of i

  10. ZeHanz
    • 3 years ago
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    You can use the fact that there is a 30-60-90 triangle involved. This means you can find the point exactly. Sound a bit complicated, so I'll try to make a drawing... (just hold on a sec!)

  11. gjhfdfg
    • 3 years ago
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    30-60-90 triangle? O_O

  12. ZeHanz
    • 3 years ago
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    Here is what I mean: (It is drawn as point D)

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  13. ZeHanz
    • 3 years ago
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    The circle has a radius 10.

  14. gjhfdfg
    • 3 years ago
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    Ah Ok, I get it.!

  15. ZeHanz
    • 3 years ago
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    You can recognise it by the combination of numbers, e.g. 2+2√3 i, or 5√3-5i...

  16. gjhfdfg
    • 3 years ago
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    Got it

  17. ZeHanz
    • 3 years ago
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    Nice!

  18. ZeHanz
    • 3 years ago
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    (Don't mean to be rude, but this image could also help - even if you already understand ;) )

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  19. gjhfdfg
    • 3 years ago
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    How would I plot 2 + i ? Would it make the 2 on the y axis also?

  20. ZeHanz
    • 3 years ago
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    2 to the right, 1 up: a+bi corresponds to point (a, b)...

  21. gjhfdfg
    • 3 years ago
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    Alrighty, thank you.!

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