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jacobian
 one year ago
Best ResponseYou've already chosen the best response.0dw:1360696905475:dw

ZeHanz
 one year ago
Best ResponseYou've already chosen the best response.0Do you mean:\[\int\limits_{k+\Delta k}^{k\Delta k}A \cos(kx) dk\]In that case: A and x are considered to be constants, so you get:\[\left[ \frac{ A }{ x }\sin(kx) \right]_{k\Delta k}^{k+\Delta k}\]Now subtitute values for k and subtract. On the other hand: shouldn't different variable names be used for the boundaries?

jacobian
 one year ago
Best ResponseYou've already chosen the best response.0i have it but the y are saying the final answer is dw:1360697434010:dw

ZeHanz
 one year ago
Best ResponseYou've already chosen the best response.0OK, let's try it:\[\frac{ A }{ x }(\sin((k+\Delta k)x)\sin((k\Delta k)x)\] To get further, you need to remember the formula of Simpson for the difference of two sine functions: sin(a)sin(b)=2cos((a+b)/2)sin((ab)/2), but I have not (yet) got that answer of yours...

jacobian
 one year ago
Best ResponseYou've already chosen the best response.0@experimentX ,@ZeHanz ,@phi help me pls

experimentX
 one year ago
Best ResponseYou've already chosen the best response.2\[ \frac{2A \Delta k x \cos( kx) }{x} = 2A \Delta k \cos (kx)\]

jacobian
 one year ago
Best ResponseYou've already chosen the best response.0by further simplifying i got this dw:1360699433822:dw

experimentX
 one year ago
Best ResponseYou've already chosen the best response.2dw:1360699738616:dw

jacobian
 one year ago
Best ResponseYou've already chosen the best response.0thanx for trying maybe they have made the mistake

experimentX
 one year ago
Best ResponseYou've already chosen the best response.2i have class at 7 in the morning ... sorry ... i gotta sleep now!!
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