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anonymous
 3 years ago
compute the following integral
anonymous
 3 years ago
compute the following integral

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360696905475:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Do you mean:\[\int\limits_{k+\Delta k}^{k\Delta k}A \cos(kx) dk\]In that case: A and x are considered to be constants, so you get:\[\left[ \frac{ A }{ x }\sin(kx) \right]_{k\Delta k}^{k+\Delta k}\]Now subtitute values for k and subtract. On the other hand: shouldn't different variable names be used for the boundaries?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i have it but the y are saying the final answer is dw:1360697434010:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0OK, let's try it:\[\frac{ A }{ x }(\sin((k+\Delta k)x)\sin((k\Delta k)x)\] To get further, you need to remember the formula of Simpson for the difference of two sine functions: sin(a)sin(b)=2cos((a+b)/2)sin((ab)/2), but I have not (yet) got that answer of yours...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@experimentX ,@ZeHanz ,@phi help me pls

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.2\[ \frac{2A \Delta k x \cos( kx) }{x} = 2A \Delta k \cos (kx)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0by further simplifying i got this dw:1360699433822:dw

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.2dw:1360699738616:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thanx for trying maybe they have made the mistake

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.2i have class at 7 in the morning ... sorry ... i gotta sleep now!!
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