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jacobianBest ResponseYou've already chosen the best response.0
dw:1360696905475:dw
 one year ago

ZeHanzBest ResponseYou've already chosen the best response.0
Do you mean:\[\int\limits_{k+\Delta k}^{k\Delta k}A \cos(kx) dk\]In that case: A and x are considered to be constants, so you get:\[\left[ \frac{ A }{ x }\sin(kx) \right]_{k\Delta k}^{k+\Delta k}\]Now subtitute values for k and subtract. On the other hand: shouldn't different variable names be used for the boundaries?
 one year ago

jacobianBest ResponseYou've already chosen the best response.0
i have it but the y are saying the final answer is dw:1360697434010:dw
 one year ago

ZeHanzBest ResponseYou've already chosen the best response.0
OK, let's try it:\[\frac{ A }{ x }(\sin((k+\Delta k)x)\sin((k\Delta k)x)\] To get further, you need to remember the formula of Simpson for the difference of two sine functions: sin(a)sin(b)=2cos((a+b)/2)sin((ab)/2), but I have not (yet) got that answer of yours...
 one year ago

jacobianBest ResponseYou've already chosen the best response.0
@experimentX ,@ZeHanz ,@phi help me pls
 one year ago

experimentXBest ResponseYou've already chosen the best response.2
\[ \frac{2A \Delta k x \cos( kx) }{x} = 2A \Delta k \cos (kx)\]
 one year ago

jacobianBest ResponseYou've already chosen the best response.0
by further simplifying i got this dw:1360699433822:dw
 one year ago

experimentXBest ResponseYou've already chosen the best response.2
dw:1360699738616:dw
 one year ago

jacobianBest ResponseYou've already chosen the best response.0
thanx for trying maybe they have made the mistake
 one year ago

experimentXBest ResponseYou've already chosen the best response.2
i have class at 7 in the morning ... sorry ... i gotta sleep now!!
 one year ago
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