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jacobian Group TitleBest ResponseYou've already chosen the best response.0
dw:1360696905475:dw
 one year ago

ZeHanz Group TitleBest ResponseYou've already chosen the best response.0
Do you mean:\[\int\limits_{k+\Delta k}^{k\Delta k}A \cos(kx) dk\]In that case: A and x are considered to be constants, so you get:\[\left[ \frac{ A }{ x }\sin(kx) \right]_{k\Delta k}^{k+\Delta k}\]Now subtitute values for k and subtract. On the other hand: shouldn't different variable names be used for the boundaries?
 one year ago

jacobian Group TitleBest ResponseYou've already chosen the best response.0
i have it but the y are saying the final answer is dw:1360697434010:dw
 one year ago

ZeHanz Group TitleBest ResponseYou've already chosen the best response.0
OK, let's try it:\[\frac{ A }{ x }(\sin((k+\Delta k)x)\sin((k\Delta k)x)\] To get further, you need to remember the formula of Simpson for the difference of two sine functions: sin(a)sin(b)=2cos((a+b)/2)sin((ab)/2), but I have not (yet) got that answer of yours...
 one year ago

jacobian Group TitleBest ResponseYou've already chosen the best response.0
@experimentX ,@ZeHanz ,@phi help me pls
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.2
\[ \frac{2A \Delta k x \cos( kx) }{x} = 2A \Delta k \cos (kx)\]
 one year ago

jacobian Group TitleBest ResponseYou've already chosen the best response.0
by further simplifying i got this dw:1360699433822:dw
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.2
dw:1360699738616:dw
 one year ago

jacobian Group TitleBest ResponseYou've already chosen the best response.0
thanx for trying maybe they have made the mistake
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.2
i have class at 7 in the morning ... sorry ... i gotta sleep now!!
 one year ago
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