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gjhfdfg
 3 years ago
Having trouble with the substitution method,
gjhfdfg
 3 years ago
Having trouble with the substitution method,

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gjhfdfg
 3 years ago
Best ResponseYou've already chosen the best response.0I've attempted it several times but answers come out different each time. & I'm clueless to why.

alrightatmaths
 3 years ago
Best ResponseYou've already chosen the best response.0What are the equations?

Kweku
 3 years ago
Best ResponseYou've already chosen the best response.0can you give us the equation for us to try it and see where the problem is?

gjhfdfg
 3 years ago
Best ResponseYou've already chosen the best response.0Its, dw:1360705833711:dw

gjhfdfg
 3 years ago
Best ResponseYou've already chosen the best response.0My answers came out from 4 to somehow I got .14446 etc..

gjhfdfg
 3 years ago
Best ResponseYou've already chosen the best response.0So I know Im doing it wrong somehow

alrightatmaths
 3 years ago
Best ResponseYou've already chosen the best response.0Get the first equation equal to x. So x = 2y5. Then sustitute that in.

alrightatmaths
 3 years ago
Best ResponseYou've already chosen the best response.0(2y5)^2 + y^2  25 = 0

alrightatmaths
 3 years ago
Best ResponseYou've already chosen the best response.04y^2  20y +25  25 = 0

Kweku
 3 years ago
Best ResponseYou've already chosen the best response.0I think alrightatmaths is right.

alrightatmaths
 3 years ago
Best ResponseYou've already chosen the best response.0Thank you Kweku :)

gjhfdfg
 3 years ago
Best ResponseYou've already chosen the best response.0Would the 0 & 4 have a fraction beside?

ArTFis
 3 years ago
Best ResponseYou've already chosen the best response.1Just make sure you have the variables on one side and the the whole numbers or fractions on the other side. {2y  x = 5 {2x + 2y  25 = 0 In this case, subtract 2y on both sides and you should get x = 5  2y. Then divide 1 due to the x on both sides. You'll then have x = 5 + 2y. Now plug in the x = 5 + 2y into the second equation. This should help you solve for y. It'll end up being 2(5 + 2y) + 2y  25 = 0 Next it'll be substituted to 10 + 4y +2y 25 = 0. Put variables on one side and the whole numbers on the other side. The whole numbers are "negative," so you should now "add" 10 and 25 on both sides. You should get in the end, 6y = 35. Divide 6 on both sides. It should be fine if you get fractions or not. This is how I learned it. Not every set of system of equations are going to be easy. It may deal with whole numbers and/or fractions. Once you find one of the values such as y or x, then plug in the y or x value into the opposite equation that you didn't use to find that value. That's how it should be I believe.

gjhfdfg
 3 years ago
Best ResponseYou've already chosen the best response.0Alrighty, I got it thanks.!
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