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gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
I've attempted it several times but answers come out different each time. & I'm clueless to why.
 one year ago

alrightatmaths Group TitleBest ResponseYou've already chosen the best response.0
What are the equations?
 one year ago

Kweku Group TitleBest ResponseYou've already chosen the best response.0
can you give us the equation for us to try it and see where the problem is?
 one year ago

gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
Its, dw:1360705833711:dw
 one year ago

gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
My answers came out from 4 to somehow I got .14446 etc..
 one year ago

gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
So I know Im doing it wrong somehow
 one year ago

alrightatmaths Group TitleBest ResponseYou've already chosen the best response.0
Get the first equation equal to x. So x = 2y5. Then sustitute that in.
 one year ago

alrightatmaths Group TitleBest ResponseYou've already chosen the best response.0
(2y5)^2 + y^2  25 = 0
 one year ago

alrightatmaths Group TitleBest ResponseYou've already chosen the best response.0
4y^2  20y +25  25 = 0
 one year ago

alrightatmaths Group TitleBest ResponseYou've already chosen the best response.0
5y^2  20y = 0
 one year ago

alrightatmaths Group TitleBest ResponseYou've already chosen the best response.0
5y(y4)=0
 one year ago

alrightatmaths Group TitleBest ResponseYou've already chosen the best response.0
y=4 or y=0
 one year ago

Kweku Group TitleBest ResponseYou've already chosen the best response.0
I think alrightatmaths is right.
 one year ago

alrightatmaths Group TitleBest ResponseYou've already chosen the best response.0
Thank you Kweku :)
 one year ago

gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
Would the 0 & 4 have a fraction beside?
 one year ago

ArTFis Group TitleBest ResponseYou've already chosen the best response.1
Just make sure you have the variables on one side and the the whole numbers or fractions on the other side. {2y  x = 5 {2x + 2y  25 = 0 In this case, subtract 2y on both sides and you should get x = 5  2y. Then divide 1 due to the x on both sides. You'll then have x = 5 + 2y. Now plug in the x = 5 + 2y into the second equation. This should help you solve for y. It'll end up being 2(5 + 2y) + 2y  25 = 0 Next it'll be substituted to 10 + 4y +2y 25 = 0. Put variables on one side and the whole numbers on the other side. The whole numbers are "negative," so you should now "add" 10 and 25 on both sides. You should get in the end, 6y = 35. Divide 6 on both sides. It should be fine if you get fractions or not. This is how I learned it. Not every set of system of equations are going to be easy. It may deal with whole numbers and/or fractions. Once you find one of the values such as y or x, then plug in the y or x value into the opposite equation that you didn't use to find that value. That's how it should be I believe.
 one year ago

gjhfdfg Group TitleBest ResponseYou've already chosen the best response.0
Alrighty, I got it thanks.!
 one year ago
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