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find the volume of the given solid: under the plane x+2y-z=0, and above the region bounded by y=x and y x^4

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find the value for x

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Other answers:

where do the graphs of y=x and y=x^4 intersect?
that's one of the intersection points, yes and the other?
x=16 is not an intersection, set the two equations equal and solve:\[x=x^4\]\[x^4-x=0\]\[x^3(x-1)=0\]so the intersections are x=1 and x=?
typo, should be\[x^4=x\]\[x^4-x=0\]\[x(x^3-1)=0\]
-1 to 1
\[x(x^3-1)=0\implies x=0\text{ or }x^3-1=0\implies x=1\]so\[x=\{0,1\}\]try drawing the graphs out if you doubt that

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