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|dw:1360708771803:dw|

what is the equation of this part of the area?|dw:1360709404014:dw|

y=2x?

@TuringTest yes i can see that

so -1/3?

y-1 = -1/3 (x-1)?

no, because (1,1) is not one of the points on the diagonal line

ok

the only one that i can use the (1,2) and (1,4)

y-2= -1/3 (x-1)

yes, now solve for y...

y= -1/3x+1/3 (+2)
y=-1/3 x+7/3

yes, and now you need the line that bounds the region below:|dw:1360710827125:dw|

same using slope

really is calc 3

@TuringTest is 1?

x=1, 4 and y= 1 , 1/3x+7/3?

yes :)

\[\int\limits_{1}^{4} \int\limits_{1}^{1/3x+7/3} xy \] dy dx

the integrand is the function for z, so use that, not xy
gotta go, happy integrating!

@TuringTest thank you so much

sorry is not z=2x+y^2 i just mistype
the book is really saying xy