## farmergirl411 2 years ago In the forrest the population of gray squirrels oscillates between a high of 5700 on January 1 (t=0)and a low of 2100 in July 1(t=6), Find a function for the population p(t) of grey squirrels in terms of time t months

1. j814wong

First you want to find the slope of teh graph from t=0 to t=6. Just use the slope formula.

2. farmergirl411

I'm not quit sure how to do this problem so I need more info than that

3. j814wong

After that, apply the slope to the formula, y=mx+b where m equals the slope. To solve for b, plug in either the first set of coordinates, (0,5700) or the second one (6,2100). If you get the right slope, the b value will be equal either way. Now plug in m and b in y=mx+b and you're done.

4. farmergirl411

I understand how to the rest after the slope can you just help me with the slope

5. j814wong

The slope formula is \[m= (y _{2}-y _{1})/(x _{2}-x _{1})\] The x value is the time and the y value is the population since the population varies with time. As such, time is teh independent variable, x.

6. farmergirl411

7. j814wong

The slope should be a -6. Did you do 5700-2100 instead of 2100-5700?

8. j814wong

It is importable to be very careful with this. y2 and x2 mean the second end of teh slope, right of the first end, y1 and x1. 5700 is at t=0 while 2100 is at t=6 so 2100 is y2 value.

9. farmergirl411

I didi that and you get 3600. sO then you take 3600/6=600 and m=600. Then you do5700=600(0)+b. and b=5700

10. farmergirl411

you just meany=-600x+57000 now good

11. j814wong

That's right

12. j814wong

m=(2100-5700)/(6-0)=-600

13. farmergirl411

ok so then that is my answer right

14. j814wong

Yeah

15. farmergirl411

p(t)=-600x+5700

16. j814wong

Correct

17. farmergirl411

thanks

18. j814wong

You're welcome