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anonymous
 3 years ago
In the forrest the population of gray squirrels oscillates between a high of 5700 on January 1 (t=0)and a low of 2100 in July 1(t=6),
Find a function for the population p(t)
of grey squirrels in terms of time t months
anonymous
 3 years ago
In the forrest the population of gray squirrels oscillates between a high of 5700 on January 1 (t=0)and a low of 2100 in July 1(t=6), Find a function for the population p(t) of grey squirrels in terms of time t months

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0First you want to find the slope of teh graph from t=0 to t=6. Just use the slope formula.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm not quit sure how to do this problem so I need more info than that

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0After that, apply the slope to the formula, y=mx+b where m equals the slope. To solve for b, plug in either the first set of coordinates, (0,5700) or the second one (6,2100). If you get the right slope, the b value will be equal either way. Now plug in m and b in y=mx+b and you're done.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I understand how to the rest after the slope can you just help me with the slope

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The slope formula is \[m= (y _{2}y _{1})/(x _{2}x _{1})\] The x value is the time and the y value is the population since the population varies with time. As such, time is teh independent variable, x.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so is the answer y=600x+5700

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The slope should be a 6. Did you do 57002100 instead of 21005700?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It is importable to be very careful with this. y2 and x2 mean the second end of teh slope, right of the first end, y1 and x1. 5700 is at t=0 while 2100 is at t=6 so 2100 is y2 value.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I didi that and you get 3600. sO then you take 3600/6=600 and m=600. Then you do5700=600(0)+b. and b=5700

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you just meany=600x+57000 now good

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0m=(21005700)/(60)=600

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok so then that is my answer right
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