anonymous
  • anonymous
Determine the slope of the graph
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
m=-2 or is it undefined?
geerky42
  • geerky42
\[m = \dfrac{y_2 - y_1}{x_2 - x_1}\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
but it goes across -2..
geerky42
  • geerky42
It does. Do you know how to use slope formula?
anonymous
  • anonymous
Y2-Y1/X2-X1
geerky42
  • geerky42
Right. Use this formula to find m.
geerky42
  • geerky42
This site may help you. http://www.purplemath.com/modules/slope.htm
anonymous
  • anonymous
I know how to use it, but I'm asking would the slope be -2 or is it undefined?
geerky42
  • geerky42
Neither.
anonymous
  • anonymous
undefined
geerky42
  • geerky42
No, it's not undefined.
anonymous
  • anonymous
no it's zero undifined is up and down
anonymous
  • anonymous
me???
geerky42
  • geerky42
Yes.
anonymous
  • anonymous
oh okay :) haha thanks

Looking for something else?

Not the answer you are looking for? Search for more explanations.