Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

How did I get this wrong? http://prntscr.com/sjlgj

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

Just curious. It marked it wrong but I'm sure I got it right. Look: x^2 ---- x^6 = 1 ---- x^-4 Now to make it positive we put it in the numerator x^4 ---- 1 Which is just equal to x^4
\[\large \frac{x^2}{x^6} \qquad = \qquad x^{2-6} \qquad = \qquad x^{-4}\]Do you see the mistake you made? You had the correct power, but when you divide, you should be left with your X in the numerator, not the bottom one.
I don't think so. \[\frac{ x^2 }{ x^6 } \rightarrow \frac{ 1 }{ x^6 - x^2 } \rightarrow \frac{ 1 }{ x^-4 } \rightarrow \frac{ x^4 }{ 1 }\rightarrow x^4\] We subtract the denominator from the numerator.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

\[\large \dfrac{x^a}{x^b} = x^{a - b} = \dfrac{1}{x^{b - a}}\]
You could write it like this if you wanted.\[\large \frac{x^2}{x^6} \qquad = \qquad \frac{1}{x^6x^{-2}} \qquad =\qquad \frac{1}{x^{6-2}} \qquad =\qquad \frac{1}{x^4} \qquad = \qquad x^{-4}\]
Zepdrix is right, you know.
You have the right idea (although the notation is a bit sloppy). You just made a tiny mistake, when you subtracted 2 from 6, it should give you `positive` 4.
If that's true, it should be -4, \[\frac{ 1 }{ x^4 }\] would be fine.
Yes that would be a fine answer! :)
Yeah. Most people hate negative exponents, so it's good enough.
But if... \[\frac{ x^6 }{ x^5 } = 6 - 5\] Why would \[\frac{ x^5 }{ x^6} = 6 - 5, too?\]
No, look at my 'formula' above here.
\[\large \frac{x^5}{x^6}=x^{5-6}\] Yah your numbers are a little backwards on the second example. :) You always subtract the BOTTOM number, it doesn't matter which number is smaller. Always subtract the power in the denominator.
lololol good ole morgan freeman XDDD

Not the answer you are looking for?

Search for more explanations.

Ask your own question