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 one year ago
E^x3=e^x someone please help me figure out how to solve the exponential equation! I keep coming up with this being undefined!!!
 one year ago
E^x3=e^x someone please help me figure out how to solve the exponential equation! I keep coming up with this being undefined!!!

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whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1\[e^{x3} = e^{x}\]Is that the equation? Are you doing exponentials with complex numbers?

jennag
 one year ago
Best ResponseYou've already chosen the best response.0No it is e^x  3 = e^x

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2\[e^x3=e^{x}\]

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2are you trying to solve for x?

jennag
 one year ago
Best ResponseYou've already chosen the best response.0Yes! I believe that's what you do when you are solving An exponential equation right?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2\[e^x3=e^{x}\]\[e^x3+e^{x}=0\]\[e^{2x}3e^x+1=0\] now substitute \(e^x=m\) \[m^23m+1=0\] solve this for m

jennag
 one year ago
Best ResponseYou've already chosen the best response.0Would it be sqrt 3m1, and sqrt 3m1

jennag
 one year ago
Best ResponseYou've already chosen the best response.0Sorry I'm on my iPad so I. Not typing it correctly

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2i got \[m=\frac{3\pm\sqrt5}{2}\]

jennag
 one year ago
Best ResponseYou've already chosen the best response.0Woahhh, okay I'm way off! How did you come up with that?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2quadratic formula?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2to get x , just take the natural logarithm of m

jennag
 one year ago
Best ResponseYou've already chosen the best response.0Got it, was doing it wrong :) thank you!!!!

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2ill check your final result when you get there, if you want

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1@jennag just for your edification, there's a thing called the hyperbolic cosine function, \(\cosh x\) which happens to be \[\cosh x =\frac{e^xe^{x}}{2}\]Your problem could have been written as \[2 \cosh x = 3\]Looks so cute and innocent, doesn't it? :)

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2note that: \[\cosh x=\frac 32\]\(\qquad\Downarrow\)\[x=\pm\operatorname{arccosh}\frac 32\]
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