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swin2013Best ResponseYou've already chosen the best response.0
\[\int\limits \sin \theta (\cos \theta +5)^7 d \theta\]
 one year ago

swin2013Best ResponseYou've already chosen the best response.0
My work: u = \[\cos \theta + 5\] \[du / d \theta\] : \[\sin \theta\] du = \[\sin \theta d \theta \] \[\theta = \pi \] \[\theta = 0 \] u = 4 u = 6 \[\int\limits\limits (from 4  6) u^7 du \]
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Hmm I think you're going from 6 to 4 actually aren't you?
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Oh it looks like you missed the negative when you took the derivative of your `u`. Maybe you just applied it to your integral, swapping the limits of integration? Or maybe you got lucky? XD lol
 one year ago

swin2013Best ResponseYou've already chosen the best response.0
lol yea, i stated the lower boundary first
 one year ago

swin2013Best ResponseYou've already chosen the best response.0
so is it [cos (theta + 5) ^8/8 ] from 46?
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
No, if you're going to go through the trouble of changing the limits, then it means you're going to solve (all the way down to a numerical value) in `u`, no longer worrying about the function of `theta` you had before.
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
\[\large \frac{1}{8}u^8_{u=4}^6\]
 one year ago

swin2013Best ResponseYou've already chosen the best response.0
lol yea, the answer is 207, 760 but i don't get that :(
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
See how you changed the limits to `u=`? Those are values you'll be plugging into `u`. Simple as that.
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
It should be 201,760. Typo maybe? :o I'll check it on Wolfram real quick to make sure I didn't make a mistake.
 one year ago

swin2013Best ResponseYou've already chosen the best response.0
i know, I changed the theta values to u values
 one year ago

swin2013Best ResponseYou've already chosen the best response.0
oh... i thought that you replace u with u= costheta +5..
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
If you `had not changed the limits of integration` then yes you would have had to do that before putting in the limits. But you changed your limits ~ No need to change back to costheta+5.
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Confused about that part? <:o
 one year ago

swin2013Best ResponseYou've already chosen the best response.0
holy cow... i looked back at my notes. that is correct lol!
 one year ago

swin2013Best ResponseYou've already chosen the best response.0
lollll thanks!! and i also have another question. but i'll post it on a different one lol
 one year ago
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