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chemENGINEER
 2 years ago
I ran into a 1st order DiffEQ that....
chemENGINEER
 2 years ago
I ran into a 1st order DiffEQ that....

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chemENGINEER
 2 years ago
Best ResponseYou've already chosen the best response.1I cannot figure which method to solve it with (linear, exact, homo, ect) x(dy/dx)=y + sqrt(x^2 + y^2)

chemENGINEER
 2 years ago
Best ResponseYou've already chosen the best response.1\[x \frac{ dy }{ dx }=y + \sqrt( x^2y^2) \]

chemENGINEER
 2 years ago
Best ResponseYou've already chosen the best response.1subtraction not addition, sorry...

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.2homogenous \(y=ux\) you have to change it; to seperable

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.2\[\large x\frac{dy}{dx}=y+\sqrt{x^2+y^2}\] correct?

chemENGINEER
 2 years ago
Best ResponseYou've already chosen the best response.1no x^2y^2 is under the radical, sorry about typo

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.2\[\large x\frac{dy}{dx}=y+\sqrt{x^2y^2}\]???

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.2so, its homogeous \(y=ux\) \[\frac{dy}{dx}=v+x\frac{dv}{dx}\] are you able to start it?

chemENGINEER
 2 years ago
Best ResponseYou've already chosen the best response.1indeed i have it from here.... thank you for the help!

Mimi_x3
 2 years ago
Best ResponseYou've already chosen the best response.2:) if you need any help; feel free to ask :)
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