A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 one year ago
Find the values of the six trigonometric functions of θ with the given constraint.Function value csc θ = 12, Constraint cot θ < 0
 one year ago
Find the values of the six trigonometric functions of θ with the given constraint.Function value csc θ = 12, Constraint cot θ < 0

This Question is Closed

PeterPan
 one year ago
Best ResponseYou've already chosen the best response.1Well, let's just draw! :D dw:1360754655516:dw

PeterPan
 one year ago
Best ResponseYou've already chosen the best response.1Cosecant is just hypotenuse over the opposite side, right?

PeterPan
 one year ago
Best ResponseYou've already chosen the best response.1dw:1360754762915:dw

PeterPan
 one year ago
Best ResponseYou've already chosen the best response.1Don't mistake cosine for cosecant, they're very different :D

PeterPan
 one year ago
Best ResponseYou've already chosen the best response.1Looked through your notes? Agree with me yet? :D

savac
 one year ago
Best ResponseYou've already chosen the best response.0im so confused. it says in my book COS(theta)=Adj/hyp

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0@PeterPan did u just assume theta here : dw:1360754965665:dw because since cot theta is negative, theta is in 3rd quadrant. and so, measure of angle theta is between 180 and 270 degrees.

PeterPan
 one year ago
Best ResponseYou've already chosen the best response.1I drew this triangle with no coordinates in mind... should I have considered them? I was going to reason out that since cotangent is going to be negative, so should tangent, as it's just the reciprocal of tangent. Since cosecant is positive, so should sine, and since tangent, which is just sine over cosine, is negative, so should cosine and secant. :>

PeterPan
 one year ago
Best ResponseYou've already chosen the best response.1And lol @hartnn Cotangent is positive in the 3rd quadrant...

savac
 one year ago
Best ResponseYou've already chosen the best response.0im stll confused sir or ma'am

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0sorry to confuse you savac , we have , cot as negative, means tan is negative. thats in 2nd or 3rd quadrant, now cosec is positive, means sin is positive, so, angle theta is in 2nd quadrant only. did u get this, first ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0and we need to consider this ...as now the triangle will look like : dw:1360755574255:dw

savac
 one year ago
Best ResponseYou've already chosen the best response.0no, i got for my answers sin=1/12, cos=\[\sqrt{143}\] /12 tan=1/\[\sqrt{143}\] csc= 12 sec=12/\[\sqrt{143}\] cot=\[\sqrt{143}\]/1

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0you gotthat using identities, right ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0okk, just make the cos, sec, tan and cot answers as negative. because theta lies in 2nd quadrant as i explained, where all these are negative.

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0like \(\csc ^2 \theta 1 = \cot^2 \theta \\ \cot^2 \theta = 1441=143 \\ \cot \theta = \pm \sqrt{143} \) now we select NEGATIVE root , because cot <0 do, same thing for cos, sec, tan

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0*so, \(\cot \theta = \sqrt {143}\)

savac
 one year ago
Best ResponseYou've already chosen the best response.0so you use the same equation for cos, sec, tan

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0same ? no for tan use tan = 1/ cot (since, you have cot) for sin use, sin = 1/csc (since, you have csc) for cos, use cos = tan / sin (since, now u have both, tan and sin) for sec, use sec = 1/ cos (since, now u have cos)

savac
 one year ago
Best ResponseYou've already chosen the best response.0ok so my answers would be sin=1/12 cos=\[\sqrt{143}\]/12 tan= 1/\[\sqrt{143}\] csc= 12 sec=12/\[\sqrt{143}\] cot=\[\sqrt{143}\]

PeterPan
 one year ago
Best ResponseYou've already chosen the best response.1Really sorry about disappearing, my internet isn't friendly to me today :(

savac
 one year ago
Best ResponseYou've already chosen the best response.0its ok. i am just glad you helped me. Thank you very much

savac
 one year ago
Best ResponseYou've already chosen the best response.0could you help me with a nother problem im having trouble with?
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.