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A uniform solid cylinder of diameter 14cm rolls with out slipping with angular velocity 25 rad/s . The cylinder suddenly contacts a plane inclined at an angle theta. The Value of theta which Brings the cylinder immediately to rest is ?

Physics
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|dw:1360757173484:dw|
won't 90 degrees do?
oh wait.. that ll just bounce it back i guess

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never mind!
|dw:1360767373040:dw| Linear velocity before = wr = 25*0.07 = 1.75 let it remain in contact with plane for time dt, then, (Nsinx)dt = m(1.75) also, it stops rolling, then Tdt = I(25) where T=torque => (Ncosx)(0.07) dt= (1/2)m(0.07)^2 * 25 Divide both eqns
I do not understand the question. You cannot bring the cylinder immediately to rest. That would mean you make a finite amount of energy disappear in an infinitesimal amount of time. You would need for that an infinite power, which is not physically acceptable.

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