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mathslover

  • 2 years ago

Rajesh went out between 5 and 6 for a work. He came to home between 6 and 7. When he came he saw that the hands have exactly changed places. When did Rajesh went out?

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  1. mathslover
    • 2 years ago
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    @amistre64 @sami-21 @ghazi @Callisto Please help

  2. ghazi
    • 2 years ago
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    well by changing hands, what do you mean, does it mean, interchanging position of hour and minute hand?

  3. mathslover
    • 2 years ago
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    I also don't know what does the book mean by it but I do have the answer. Ok! Let us take the meaning as specified by you @ghazi ... what answer you arrived ?

  4. ghazi
    • 2 years ago
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    well i consider as interchanging of minute and hour hands , which means both will acquire new position if turned by 180 degrees , lets say its 6 o clock then minute hand is at 12 and hour is at 6 and if hands are interchanged then it will be 12.30 , thats what i concluded

  5. ghazi
    • 2 years ago
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    not 12.30 but a bit less, or lets say its 5 past 7 then if hands are interchanged , it will be 1.35 , thats what i can think of , but i guess here book says about mirror image like 5.25 and its mirror image is 6.40 , which satisfies your question

  6. mathslover
    • 2 years ago
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    No but that is not the answer...

  7. mathslover
    • 2 years ago
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    I think the question is wrong,,,,,

  8. ghazi
    • 2 years ago
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    changing hands is confusing me , i think its 5.30 and then 6.25

  9. ghazi
    • 2 years ago
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    like her left at 5.30 and if hands are changed it will be 6.25

  10. ghazi
    • 2 years ago
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    *he

  11. amistre64
    • 2 years ago
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    yes, clocks used to have hands on them to tell the time with :)

  12. amistre64
    • 2 years ago
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    |dw:1360761423073:dw|

  13. ghazi
    • 2 years ago
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    unfortunately its obsolete and now digital watch is preferred lol for higher precision and accuracy

  14. ghazi
    • 2 years ago
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    so i guess i was correct lol

  15. amistre64
    • 2 years ago
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    5.30 to 6.30 is a suitable result

  16. amistre64
    • 2 years ago
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    but then we are talking about angles .... and not time itself lol

  17. mathslover
    • 2 years ago
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    Well I don't think tht question means for mirror images..

  18. ghazi
    • 2 years ago
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    exactly, i am trying to think of mathematical explanation and @mathslover we didnt use mirror image , we just interchanged the position of hands in your given time interval, 5 at 6 and 6 at 5 ;)

  19. amistre64
    • 2 years ago
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    |dw:1360761555731:dw| we have different angular speeds to acowingspan for

  20. mathslover
    • 2 years ago
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    oh sorry

  21. ghazi
    • 2 years ago
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    its okay but try to think that mathematically :) that would be fun

  22. amistre64
    • 2 years ago
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    lol; so wither account is a bad word? or was my typo a bad wrod

  23. ghazi
    • 2 years ago
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    wingspan stands for male genital lol

  24. ghazi
    • 2 years ago
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    i was horrified by your word , what you wanted to write lol hehe

  25. amistre64
    • 2 years ago
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    the hour hand has a constant speed of 360 per hour; the minute hand has a speed of 360/60 per hour. if you can narrow down how to account for a general position you can use the speeds to find a related rates problem maybe .... or it could be one of the harry and sally paint a room things

  26. amistre64
    • 2 years ago
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    we know the time had to be less than an hour, since the minute hand didnt make it all the way around ....

  27. amistre64
    • 2 years ago
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    lets assume 50 minutes just to cover the span from the 5 to the 7 and my speeds are off

  28. amistre64
    • 2 years ago
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    minute hand is 360 per hour; and hour hand is 360+360/12

  29. ghazi
    • 2 years ago
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    minute hand moves faster than hour, minute hand completes 360 degrees in one hour and hour hand covers only 30 degree in one hour

  30. amistre64
    • 2 years ago
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    ...lol, its been so long since i looked at a clock i spose

  31. amistre64
    • 2 years ago
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    lets assume for a minute that im an idiot ;)

  32. amistre64
    • 2 years ago
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    so a tortise and a hare are chasing ech other around a track at defined speeds. how long does it take the tortise to reach where the hare was, at the same time that the hare reaches the position that the tortise was ....

  33. AravindG
    • 2 years ago
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    but the hare slept on its way :O

  34. amistre64
    • 2 years ago
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    lazy hares :)

  35. mathslover
    • 2 years ago
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    hehe

  36. ghazi
    • 2 years ago
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    alright fellas ;) i guess we are done ;) lets go back to get lazy

  37. amistre64
    • 2 years ago
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    also need to determine the angle of separation at a given time .... im sure someones figured this out in like 1587bc

  38. amistre64
    • 2 years ago
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    |dw:1360762766659:dw| for a given degree alpha we need to determine when "equivalent" distances get traveled at a given speed; when alpha = 360-alpha does that make any sense?

  39. amistre64
    • 2 years ago
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    the time interval is the same for each distance traveled \[hour: \frac{30^o}{60sec}t=\alpha^o\\minute:\frac{360^o}{60sec}t=360^o-\alpha\] 2 equations in 2 unknowns right?

  40. amistre64
    • 2 years ago
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    \[\frac{390^o}{60}t=360^o\] \[t=60sec~\frac{360^o}{390^o}=55\frac{5}{13}sec\]

  41. amistre64
    • 2 years ago
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    \[\alpha=\frac{30^o}{60sec}*\frac{720}{13}sec=(\frac{360}{13})^o\] at what time between 5 and 6 are the hands that many degrees apart? id start at noon and do some additional calculations

  42. amistre64
    • 2 years ago
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    or start at 5 :)

  43. amistre64
    • 2 years ago
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    |dw:1360764111867:dw| \[\frac{360^o}{60}t-(150^o+\frac{30^o}{60}t)=(\frac{360}{13})^o\] solve for t

  44. amistre64
    • 2 years ago
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    and im writing sec for minutes for some reason ... ; so i get 5:32.31 as a starting time

  45. amistre64
    • 2 years ago
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    at any rate, i got a good idea, might have the speeds off tho so dbl chk if your interested in it:)

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