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mathslover Group Title

Rajesh went out between 5 and 6 for a work. He came to home between 6 and 7. When he came he saw that the hands have exactly changed places. When did Rajesh went out?

  • one year ago
  • one year ago

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  1. mathslover Group Title
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    @amistre64 @sami-21 @ghazi @Callisto Please help

    • one year ago
  2. ghazi Group Title
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    well by changing hands, what do you mean, does it mean, interchanging position of hour and minute hand?

    • one year ago
  3. mathslover Group Title
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    I also don't know what does the book mean by it but I do have the answer. Ok! Let us take the meaning as specified by you @ghazi ... what answer you arrived ?

    • one year ago
  4. ghazi Group Title
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    well i consider as interchanging of minute and hour hands , which means both will acquire new position if turned by 180 degrees , lets say its 6 o clock then minute hand is at 12 and hour is at 6 and if hands are interchanged then it will be 12.30 , thats what i concluded

    • one year ago
  5. ghazi Group Title
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    not 12.30 but a bit less, or lets say its 5 past 7 then if hands are interchanged , it will be 1.35 , thats what i can think of , but i guess here book says about mirror image like 5.25 and its mirror image is 6.40 , which satisfies your question

    • one year ago
  6. mathslover Group Title
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    No but that is not the answer...

    • one year ago
  7. mathslover Group Title
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    I think the question is wrong,,,,,

    • one year ago
  8. ghazi Group Title
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    changing hands is confusing me , i think its 5.30 and then 6.25

    • one year ago
  9. ghazi Group Title
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    like her left at 5.30 and if hands are changed it will be 6.25

    • one year ago
  10. ghazi Group Title
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    *he

    • one year ago
  11. amistre64 Group Title
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    yes, clocks used to have hands on them to tell the time with :)

    • one year ago
  12. amistre64 Group Title
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    |dw:1360761423073:dw|

    • one year ago
  13. ghazi Group Title
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    unfortunately its obsolete and now digital watch is preferred lol for higher precision and accuracy

    • one year ago
  14. ghazi Group Title
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    so i guess i was correct lol

    • one year ago
  15. amistre64 Group Title
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    5.30 to 6.30 is a suitable result

    • one year ago
  16. amistre64 Group Title
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    but then we are talking about angles .... and not time itself lol

    • one year ago
  17. mathslover Group Title
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    Well I don't think tht question means for mirror images..

    • one year ago
  18. ghazi Group Title
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    exactly, i am trying to think of mathematical explanation and @mathslover we didnt use mirror image , we just interchanged the position of hands in your given time interval, 5 at 6 and 6 at 5 ;)

    • one year ago
  19. amistre64 Group Title
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    |dw:1360761555731:dw| we have different angular speeds to acowingspan for

    • one year ago
  20. mathslover Group Title
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    oh sorry

    • one year ago
  21. ghazi Group Title
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    its okay but try to think that mathematically :) that would be fun

    • one year ago
  22. amistre64 Group Title
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    lol; so wither account is a bad word? or was my typo a bad wrod

    • one year ago
  23. ghazi Group Title
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    wingspan stands for male genital lol

    • one year ago
  24. ghazi Group Title
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    i was horrified by your word , what you wanted to write lol hehe

    • one year ago
  25. amistre64 Group Title
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    the hour hand has a constant speed of 360 per hour; the minute hand has a speed of 360/60 per hour. if you can narrow down how to account for a general position you can use the speeds to find a related rates problem maybe .... or it could be one of the harry and sally paint a room things

    • one year ago
  26. amistre64 Group Title
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    we know the time had to be less than an hour, since the minute hand didnt make it all the way around ....

    • one year ago
  27. amistre64 Group Title
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    lets assume 50 minutes just to cover the span from the 5 to the 7 and my speeds are off

    • one year ago
  28. amistre64 Group Title
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    minute hand is 360 per hour; and hour hand is 360+360/12

    • one year ago
  29. ghazi Group Title
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    minute hand moves faster than hour, minute hand completes 360 degrees in one hour and hour hand covers only 30 degree in one hour

    • one year ago
  30. amistre64 Group Title
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    ...lol, its been so long since i looked at a clock i spose

    • one year ago
  31. amistre64 Group Title
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    lets assume for a minute that im an idiot ;)

    • one year ago
  32. mathslover Group Title
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    ^ http://www.edunetworking.com/PlayVideo.aspx?u=fFWIDQNe0nQ&Class=CAT%20&Subject=Logical%20Reasoning

    • one year ago
  33. amistre64 Group Title
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    so a tortise and a hare are chasing ech other around a track at defined speeds. how long does it take the tortise to reach where the hare was, at the same time that the hare reaches the position that the tortise was ....

    • one year ago
  34. AravindG Group Title
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    but the hare slept on its way :O

    • one year ago
  35. amistre64 Group Title
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    lazy hares :)

    • one year ago
  36. mathslover Group Title
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    hehe

    • one year ago
  37. ghazi Group Title
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    alright fellas ;) i guess we are done ;) lets go back to get lazy

    • one year ago
  38. amistre64 Group Title
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    also need to determine the angle of separation at a given time .... im sure someones figured this out in like 1587bc

    • one year ago
  39. amistre64 Group Title
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    |dw:1360762766659:dw| for a given degree alpha we need to determine when "equivalent" distances get traveled at a given speed; when alpha = 360-alpha does that make any sense?

    • one year ago
  40. amistre64 Group Title
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    the time interval is the same for each distance traveled \[hour: \frac{30^o}{60sec}t=\alpha^o\\minute:\frac{360^o}{60sec}t=360^o-\alpha\] 2 equations in 2 unknowns right?

    • one year ago
  41. amistre64 Group Title
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    \[\frac{390^o}{60}t=360^o\] \[t=60sec~\frac{360^o}{390^o}=55\frac{5}{13}sec\]

    • one year ago
  42. amistre64 Group Title
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    \[\alpha=\frac{30^o}{60sec}*\frac{720}{13}sec=(\frac{360}{13})^o\] at what time between 5 and 6 are the hands that many degrees apart? id start at noon and do some additional calculations

    • one year ago
  43. amistre64 Group Title
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    or start at 5 :)

    • one year ago
  44. amistre64 Group Title
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    |dw:1360764111867:dw| \[\frac{360^o}{60}t-(150^o+\frac{30^o}{60}t)=(\frac{360}{13})^o\] solve for t

    • one year ago
  45. amistre64 Group Title
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    and im writing sec for minutes for some reason ... ; so i get 5:32.31 as a starting time

    • one year ago
  46. amistre64 Group Title
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    at any rate, i got a good idea, might have the speeds off tho so dbl chk if your interested in it:)

    • one year ago
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