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need help with a integral (sin^2(t)cos^4(t)),
I can split it up into:
((1cos(2t))/2)((1+cos(2t))/2)^2,
but the solution then takes out the constants and make it so its 1/8 infront of the integral, how do you get 1/8? I can get 1/4 but not 1/8
 one year ago
 one year ago
need help with a integral (sin^2(t)cos^4(t)), I can split it up into: ((1cos(2t))/2)((1+cos(2t))/2)^2, but the solution then takes out the constants and make it so its 1/8 infront of the integral, how do you get 1/8? I can get 1/4 but not 1/8
 one year ago
 one year ago

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TuringTestBest ResponseYou've already chosen the best response.0
The way I would do it is to apply\[\sin^2t=1\cos^2t\]them use the double angle formula\[\cos^2t=\frac12(1+\cos(2t))\]
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
you wanted to know how we get 1/8 ? [(1...)/2 ] [(1+...)/2]^2 = [1/2.....] [1/4+ ...] = [1/8 +....]
 one year ago

bretmBest ResponseYou've already chosen the best response.0
ah, i see what your saying now
 one year ago

bretmBest ResponseYou've already chosen the best response.0
it was taking the second part and squaring it and expanding it that was confusing but when I expanded it i forgot about what happened to my 2 on the bottom yes, thank you
 one year ago
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