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 one year ago
need help with a integral (sin^2(t)cos^4(t)),
I can split it up into:
((1cos(2t))/2)((1+cos(2t))/2)^2,
but the solution then takes out the constants and make it so its 1/8 infront of the integral, how do you get 1/8? I can get 1/4 but not 1/8
 one year ago
need help with a integral (sin^2(t)cos^4(t)), I can split it up into: ((1cos(2t))/2)((1+cos(2t))/2)^2, but the solution then takes out the constants and make it so its 1/8 infront of the integral, how do you get 1/8? I can get 1/4 but not 1/8

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TuringTest
 one year ago
Best ResponseYou've already chosen the best response.0The way I would do it is to apply\[\sin^2t=1\cos^2t\]them use the double angle formula\[\cos^2t=\frac12(1+\cos(2t))\]

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2you wanted to know how we get 1/8 ? [(1...)/2 ] [(1+...)/2]^2 = [1/2.....] [1/4+ ...] = [1/8 +....]

bretm
 one year ago
Best ResponseYou've already chosen the best response.0ah, i see what your saying now

bretm
 one year ago
Best ResponseYou've already chosen the best response.0it was taking the second part and squaring it and expanding it that was confusing but when I expanded it i forgot about what happened to my 2 on the bottom yes, thank you
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