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willowdavis97

  • 3 years ago

(3/x)+[13/(x-11)]

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  1. willowdavis97
    • 3 years ago
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    I got -28 for the answer but didn't know if it was right

  2. tkhunny
    • 3 years ago
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    ?? Is there a value for x?

  3. willowdavis97
    • 3 years ago
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    no just to simplify.

  4. willowdavis97
    • 3 years ago
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    its 3 over x + 13 over x-11 and I am just supposed to simplify.

  5. valentinekid
    • 3 years ago
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    given \[\frac{ 3 }{ x } + \frac{13}{x-11}\] we can multiply any term by 1, right? We want a common denominator, so try multiplying each term by a version of 1... \[\frac{x-11}{x-11}\] and \[\frac{x}{x}\] respectively to see what happens.

  6. willowdavis97
    • 3 years ago
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    I did that and after everything i got -28

  7. valentinekid
    • 3 years ago
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    If you don't have a value for x your answer should still include x. When you multiplied (x-11)/(x-11) and x/x what did you end up with?

  8. willowdavis97
    • 3 years ago
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    3x-33 over x^2-11x + 13x over x^2-11x

  9. willowdavis97
    • 3 years ago
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    would that be it or could i simplify more.

  10. valentinekid
    • 3 years ago
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    Perfect. Now that you have a common denominator, you can combine your two fractions into one, combining like terms in your numerator: [(3x-33)+13x]/(x^2-11x)

  11. willowdavis97
    • 3 years ago
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    oh okay, so in the end it would be 16x-33 over x^2-11x?

  12. valentinekid
    • 3 years ago
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    exactly! That's as simple as you can get. :) Good work

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