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willowdavis97 Group TitleBest ResponseYou've already chosen the best response.1
I got 28 for the answer but didn't know if it was right
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.0
?? Is there a value for x?
 one year ago

willowdavis97 Group TitleBest ResponseYou've already chosen the best response.1
no just to simplify.
 one year ago

willowdavis97 Group TitleBest ResponseYou've already chosen the best response.1
its 3 over x + 13 over x11 and I am just supposed to simplify.
 one year ago

valentinekid Group TitleBest ResponseYou've already chosen the best response.1
given \[\frac{ 3 }{ x } + \frac{13}{x11}\] we can multiply any term by 1, right? We want a common denominator, so try multiplying each term by a version of 1... \[\frac{x11}{x11}\] and \[\frac{x}{x}\] respectively to see what happens.
 one year ago

willowdavis97 Group TitleBest ResponseYou've already chosen the best response.1
I did that and after everything i got 28
 one year ago

valentinekid Group TitleBest ResponseYou've already chosen the best response.1
If you don't have a value for x your answer should still include x. When you multiplied (x11)/(x11) and x/x what did you end up with?
 one year ago

willowdavis97 Group TitleBest ResponseYou've already chosen the best response.1
3x33 over x^211x + 13x over x^211x
 one year ago

willowdavis97 Group TitleBest ResponseYou've already chosen the best response.1
would that be it or could i simplify more.
 one year ago

valentinekid Group TitleBest ResponseYou've already chosen the best response.1
Perfect. Now that you have a common denominator, you can combine your two fractions into one, combining like terms in your numerator: [(3x33)+13x]/(x^211x)
 one year ago

willowdavis97 Group TitleBest ResponseYou've already chosen the best response.1
oh okay, so in the end it would be 16x33 over x^211x?
 one year ago

valentinekid Group TitleBest ResponseYou've already chosen the best response.1
exactly! That's as simple as you can get. :) Good work
 one year ago
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