A circle has its center at the center of a square with 3-inch sides. Find the area of the square not covered by the circle. Round the answer to the nearest tenth.

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the diameter of the circle is 3in. Why? the diameter is parallel to a side. So we will calculate the area of the circle and subtract that value from the area of the square. so area of the square=l*w=3*3=9 area of the circle=\[\pi \times r^{2}\]=\[\pi\times 3/2^{2}\]. THIS YIELDS: \[9- 9/4 \times \pi\] then put into a calculator and get A=\[6.75 \pi\]

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