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 one year ago
Please help me get started with solving the following integral (click to see).
 one year ago
Please help me get started with solving the following integral (click to see).

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Babyslapmafro
 one year ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{}(lnx)^{2}dx\]

Babyslapmafro
 one year ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{}u ^{2}\frac{ du }{ 1/x }\] Is this the correct start before doing integration by parts?

OkayOkay
 one year ago
Best ResponseYou've already chosen the best response.0u=ln[x]^2, v=x, du=2ln[x]1/x Integration by parts: uvintegral[vdu]

OkayOkay
 one year ago
Best ResponseYou've already chosen the best response.0uvintegral[vdu]= xln[x]^2integral[2xln[x]1/x]= xln[x]^22integral[ln[x]]

OkayOkay
 one year ago
Best ResponseYou've already chosen the best response.0questions or you got it from here? You will do another integration by parts. So a total of two integration by parts to get to a simple 1dx integral.

OkayOkay
 one year ago
Best ResponseYou've already chosen the best response.0step 1: \[xln[x]^{2}\int\limits_{}^{}2x \ln [x] \frac{ 1 }{ x }\]

OkayOkay
 one year ago
Best ResponseYou've already chosen the best response.0simplify: \[xln[x]^22\int\limits_{}^{}\ln[x]dx \]

OkayOkay
 one year ago
Best ResponseYou've already chosen the best response.0\[xln[x]^22(xln[x]\int\limits_{}^{}x(1/x)dx=xln[x]^22(xln[x]\int\limits_{}^{}1dx\]

OkayOkay
 one year ago
Best ResponseYou've already chosen the best response.0\[x(\ln[x]^22\ln[x]+2)+c\]

OkayOkay
 one year ago
Best ResponseYou've already chosen the best response.0What do you think? I can show you an easy way to remember these multi step problems if you'd like....
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