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Babyslapmafro
 2 years ago
Please help me get started with solving the following integral (click to see).
Babyslapmafro
 2 years ago
Please help me get started with solving the following integral (click to see).

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Babyslapmafro
 2 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{}(lnx)^{2}dx\]

Babyslapmafro
 2 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{}u ^{2}\frac{ du }{ 1/x }\] Is this the correct start before doing integration by parts?

OkayOkay
 2 years ago
Best ResponseYou've already chosen the best response.0u=ln[x]^2, v=x, du=2ln[x]1/x Integration by parts: uvintegral[vdu]

OkayOkay
 2 years ago
Best ResponseYou've already chosen the best response.0uvintegral[vdu]= xln[x]^2integral[2xln[x]1/x]= xln[x]^22integral[ln[x]]

OkayOkay
 2 years ago
Best ResponseYou've already chosen the best response.0questions or you got it from here? You will do another integration by parts. So a total of two integration by parts to get to a simple 1dx integral.

OkayOkay
 2 years ago
Best ResponseYou've already chosen the best response.0step 1: \[xln[x]^{2}\int\limits_{}^{}2x \ln [x] \frac{ 1 }{ x }\]

OkayOkay
 2 years ago
Best ResponseYou've already chosen the best response.0simplify: \[xln[x]^22\int\limits_{}^{}\ln[x]dx \]

OkayOkay
 2 years ago
Best ResponseYou've already chosen the best response.0\[xln[x]^22(xln[x]\int\limits_{}^{}x(1/x)dx=xln[x]^22(xln[x]\int\limits_{}^{}1dx\]

OkayOkay
 2 years ago
Best ResponseYou've already chosen the best response.0\[x(\ln[x]^22\ln[x]+2)+c\]

OkayOkay
 2 years ago
Best ResponseYou've already chosen the best response.0What do you think? I can show you an easy way to remember these multi step problems if you'd like....
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