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Please help me get started with solving the following integral (click to see).
 one year ago
 one year ago
Please help me get started with solving the following integral (click to see).
 one year ago
 one year ago

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BabyslapmafroBest ResponseYou've already chosen the best response.0
\[\int\limits_{}^{}(lnx)^{2}dx\]
 one year ago

BabyslapmafroBest ResponseYou've already chosen the best response.0
\[\int\limits_{}^{}u ^{2}\frac{ du }{ 1/x }\] Is this the correct start before doing integration by parts?
 one year ago

OkayOkayBest ResponseYou've already chosen the best response.0
u=ln[x]^2, v=x, du=2ln[x]1/x Integration by parts: uvintegral[vdu]
 one year ago

OkayOkayBest ResponseYou've already chosen the best response.0
uvintegral[vdu]= xln[x]^2integral[2xln[x]1/x]= xln[x]^22integral[ln[x]]
 one year ago

OkayOkayBest ResponseYou've already chosen the best response.0
questions or you got it from here? You will do another integration by parts. So a total of two integration by parts to get to a simple 1dx integral.
 one year ago

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step 1: \[xln[x]^{2}\int\limits_{}^{}2x \ln [x] \frac{ 1 }{ x }\]
 one year ago

OkayOkayBest ResponseYou've already chosen the best response.0
simplify: \[xln[x]^22\int\limits_{}^{}\ln[x]dx \]
 one year ago

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\[xln[x]^22(xln[x]\int\limits_{}^{}x(1/x)dx=xln[x]^22(xln[x]\int\limits_{}^{}1dx\]
 one year ago

OkayOkayBest ResponseYou've already chosen the best response.0
\[x(\ln[x]^22\ln[x]+2)+c\]
 one year ago

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What do you think? I can show you an easy way to remember these multi step problems if you'd like....
 one year ago
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