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pottersheep
Group Title
Please help! "challenge" calc question. We just learned power, product, chain rules...(I have to draw it out)
 one year ago
 one year ago
pottersheep Group Title
Please help! "challenge" calc question. We just learned power, product, chain rules...(I have to draw it out)
 one year ago
 one year ago

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pottersheep Group TitleBest ResponseYou've already chosen the best response.0
dw:1360808280236:dw
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
I must evaluate that
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
I don't know how :(
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.1
use the L'hopital hint : differentiate for the numerator and the denominator
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
We haven't learned questient rule if that is what you are saying?
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
quotient*
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.1
it just the derivative of a function... u can use the basic formula : y = x^n > y ' = n*x^(n1) y = a (a is constant) > y ' = 0
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
I tried using product rule and I still got zeros in my denominator though
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.1
we neednt use the product or quotien here, just deriv each terms
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.1
derivative of x^1000  1 = ... ? derivative of x  1 = .... ?
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
ohhh because what I did was I wrote it as (X^10001)(x1)^1
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
derivative of x^1000  1 = 1000x^999 derivative of x  1 = 1?
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
What do I do now?
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.1
yes, that's right... now, just put x=1, u will get its answer
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
no quotient rule? :o
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.1
dw:1360809016288:dw NO QUOTIENT RULE :)
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
That's the right answer! Thank you, how come we dont have to use the quotient rule though if i have a fraction?
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
and there is division
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.1
sorry, icant explaind more... my english so bad :)
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
You're good at english I didnt even notice :) thank you for your time
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.1
you're welcome :)
 one year ago

SithsAndGiggles Group TitleBest ResponseYou've already chosen the best response.0
I'll try to explain why the quotient rule isn't used. What @RadEn described was L'Hopital's rule, which says that the limit of some rational function f(x)/g(x) (a ratio of f to g), where both f and g are differentiable and g(x) is nonzero, is equal to the limit of the ratio of the derivatives of f and g. \[\lim_{x\to c}\frac{f(x)}{g(x)}=\lim_{x\to c}\frac{f'(x)}{g'(x)}\] The quotient rule itself wasn't used because you do not find the derivative for f(x)/g(x), but rather f(x) and g(x) separately.
 one year ago

pottersheep Group TitleBest ResponseYou've already chosen the best response.0
Ohhhhhhh thanks!!!
 one year ago
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