pottersheep
  • pottersheep
Please help! "challenge" calc question. We just learned power, product, chain rules...(I have to draw it out)
Mathematics
schrodinger
  • schrodinger
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pottersheep
  • pottersheep
|dw:1360808280236:dw|
pottersheep
  • pottersheep
I must evaluate that
pottersheep
  • pottersheep
I don't know how :(

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RadEn
  • RadEn
use the L'hopital hint : differentiate for the numerator and the denominator
pottersheep
  • pottersheep
We haven't learned questient rule if that is what you are saying?
pottersheep
  • pottersheep
quotient*
RadEn
  • RadEn
it just the derivative of a function... u can use the basic formula : y = x^n ----> y ' = n*x^(n-1) y = a (a is constant) ---> y ' = 0
pottersheep
  • pottersheep
I tried using product rule and I still got zeros in my denominator though
RadEn
  • RadEn
we neednt use the product or quotien here, just deriv each terms
RadEn
  • RadEn
derivative of x^1000 - 1 = ... ? derivative of x - 1 = .... ?
pottersheep
  • pottersheep
ohhh because what I did was I wrote it as (X^1000-1)(x-1)^-1
pottersheep
  • pottersheep
derivative of x^1000 - 1 = 1000x^999 derivative of x - 1 = 1?
pottersheep
  • pottersheep
What do I do now?
RadEn
  • RadEn
yes, that's right... now, just put x=1, u will get its answer
pottersheep
  • pottersheep
no quotient rule? :o
RadEn
  • RadEn
|dw:1360809016288:dw| NO QUOTIENT RULE :)
pottersheep
  • pottersheep
That's the right answer! Thank you, how come we dont have to use the quotient rule though if i have a fraction?
pottersheep
  • pottersheep
and there is division
RadEn
  • RadEn
sorry, icant explaind more... my english so bad :)
pottersheep
  • pottersheep
You're good at english I didnt even notice :) thank you for your time
RadEn
  • RadEn
you're welcome :)
anonymous
  • anonymous
I'll try to explain why the quotient rule isn't used. What @RadEn described was L'Hopital's rule, which says that the limit of some rational function f(x)/g(x) (a ratio of f to g), where both f and g are differentiable and g(x) is non-zero, is equal to the limit of the ratio of the derivatives of f and g. \[\lim_{x\to c}\frac{f(x)}{g(x)}=\lim_{x\to c}\frac{f'(x)}{g'(x)}\] The quotient rule itself wasn't used because you do not find the derivative for f(x)/g(x), but rather f(x) and g(x) separately.
pottersheep
  • pottersheep
Ohhhhhhh thanks!!!

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