Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

pottersheep

  • one year ago

Please help! "challenge" calc question. We just learned power, product, chain rules...(I have to draw it out)

  • This Question is Closed
  1. pottersheep
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1360808280236:dw|

  2. pottersheep
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I must evaluate that

  3. pottersheep
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I don't know how :(

  4. RadEn
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    use the L'hopital hint : differentiate for the numerator and the denominator

  5. pottersheep
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    We haven't learned questient rule if that is what you are saying?

  6. pottersheep
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    quotient*

  7. RadEn
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    it just the derivative of a function... u can use the basic formula : y = x^n ----> y ' = n*x^(n-1) y = a (a is constant) ---> y ' = 0

  8. pottersheep
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I tried using product rule and I still got zeros in my denominator though

  9. RadEn
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    we neednt use the product or quotien here, just deriv each terms

  10. RadEn
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    derivative of x^1000 - 1 = ... ? derivative of x - 1 = .... ?

  11. pottersheep
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ohhh because what I did was I wrote it as (X^1000-1)(x-1)^-1

  12. pottersheep
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    derivative of x^1000 - 1 = 1000x^999 derivative of x - 1 = 1?

  13. pottersheep
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    What do I do now?

  14. RadEn
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes, that's right... now, just put x=1, u will get its answer

  15. pottersheep
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no quotient rule? :o

  16. RadEn
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1360809016288:dw| NO QUOTIENT RULE :)

  17. pottersheep
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    That's the right answer! Thank you, how come we dont have to use the quotient rule though if i have a fraction?

  18. pottersheep
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    and there is division

  19. RadEn
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    sorry, icant explaind more... my english so bad :)

  20. pottersheep
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You're good at english I didnt even notice :) thank you for your time

  21. RadEn
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    you're welcome :)

  22. SithsAndGiggles
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'll try to explain why the quotient rule isn't used. What @RadEn described was L'Hopital's rule, which says that the limit of some rational function f(x)/g(x) (a ratio of f to g), where both f and g are differentiable and g(x) is non-zero, is equal to the limit of the ratio of the derivatives of f and g. \[\lim_{x\to c}\frac{f(x)}{g(x)}=\lim_{x\to c}\frac{f'(x)}{g'(x)}\] The quotient rule itself wasn't used because you do not find the derivative for f(x)/g(x), but rather f(x) and g(x) separately.

  23. pottersheep
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ohhhhhhh thanks!!!

  24. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.