Please help! "challenge" calc question. We just learned power, product, chain rules...(I have to draw it out)

- pottersheep

- schrodinger

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- pottersheep

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- pottersheep

I must evaluate that

- pottersheep

I don't know how :(

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## More answers

- RadEn

use the L'hopital
hint : differentiate for the numerator and the denominator

- pottersheep

We haven't learned questient rule if that is what you are saying?

- pottersheep

quotient*

- RadEn

it just the derivative of a function...
u can use the basic formula :
y = x^n ----> y ' = n*x^(n-1)
y = a (a is constant) ---> y ' = 0

- pottersheep

I tried using product rule and I still got zeros in my denominator though

- RadEn

we neednt use the product or quotien here, just deriv each terms

- RadEn

derivative of x^1000 - 1 = ... ?
derivative of x - 1 = .... ?

- pottersheep

ohhh because what I did was I wrote it as
(X^1000-1)(x-1)^-1

- pottersheep

derivative of x^1000 - 1 = 1000x^999 derivative of x - 1 = 1?

- pottersheep

What do I do now?

- RadEn

yes, that's right...
now, just put x=1, u will get its answer

- pottersheep

no quotient rule? :o

- RadEn

|dw:1360809016288:dw|
NO QUOTIENT RULE :)

- pottersheep

That's the right answer! Thank you, how come we dont have to use the quotient rule though if i have a fraction?

- pottersheep

and there is division

- RadEn

sorry, icant explaind more... my english so bad :)

- pottersheep

You're good at english I didnt even notice :) thank you for your time

- RadEn

you're welcome :)

- anonymous

I'll try to explain why the quotient rule isn't used.
What @RadEn described was L'Hopital's rule, which says that the limit of some rational function f(x)/g(x) (a ratio of f to g), where both f and g are differentiable and g(x) is non-zero, is equal to the limit of the ratio of the derivatives of f and g.
\[\lim_{x\to c}\frac{f(x)}{g(x)}=\lim_{x\to c}\frac{f'(x)}{g'(x)}\]
The quotient rule itself wasn't used because you do not find the derivative for f(x)/g(x), but rather f(x) and g(x) separately.

- pottersheep

Ohhhhhhh thanks!!!

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