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pottersheep Group Title

Please help! "challenge" calc question. We just learned power, product, chain rules...(I have to draw it out)

  • one year ago
  • one year ago

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  1. pottersheep Group Title
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    |dw:1360808280236:dw|

    • one year ago
  2. pottersheep Group Title
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    I must evaluate that

    • one year ago
  3. pottersheep Group Title
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    I don't know how :(

    • one year ago
  4. RadEn Group Title
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    use the L'hopital hint : differentiate for the numerator and the denominator

    • one year ago
  5. pottersheep Group Title
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    We haven't learned questient rule if that is what you are saying?

    • one year ago
  6. pottersheep Group Title
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    quotient*

    • one year ago
  7. RadEn Group Title
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    it just the derivative of a function... u can use the basic formula : y = x^n ----> y ' = n*x^(n-1) y = a (a is constant) ---> y ' = 0

    • one year ago
  8. pottersheep Group Title
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    I tried using product rule and I still got zeros in my denominator though

    • one year ago
  9. RadEn Group Title
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    we neednt use the product or quotien here, just deriv each terms

    • one year ago
  10. RadEn Group Title
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    derivative of x^1000 - 1 = ... ? derivative of x - 1 = .... ?

    • one year ago
  11. pottersheep Group Title
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    ohhh because what I did was I wrote it as (X^1000-1)(x-1)^-1

    • one year ago
  12. pottersheep Group Title
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    derivative of x^1000 - 1 = 1000x^999 derivative of x - 1 = 1?

    • one year ago
  13. pottersheep Group Title
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    What do I do now?

    • one year ago
  14. RadEn Group Title
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    yes, that's right... now, just put x=1, u will get its answer

    • one year ago
  15. pottersheep Group Title
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    no quotient rule? :o

    • one year ago
  16. RadEn Group Title
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    |dw:1360809016288:dw| NO QUOTIENT RULE :)

    • one year ago
  17. pottersheep Group Title
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    That's the right answer! Thank you, how come we dont have to use the quotient rule though if i have a fraction?

    • one year ago
  18. pottersheep Group Title
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    and there is division

    • one year ago
  19. RadEn Group Title
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    sorry, icant explaind more... my english so bad :)

    • one year ago
  20. pottersheep Group Title
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    You're good at english I didnt even notice :) thank you for your time

    • one year ago
  21. RadEn Group Title
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    you're welcome :)

    • one year ago
  22. SithsAndGiggles Group Title
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    I'll try to explain why the quotient rule isn't used. What @RadEn described was L'Hopital's rule, which says that the limit of some rational function f(x)/g(x) (a ratio of f to g), where both f and g are differentiable and g(x) is non-zero, is equal to the limit of the ratio of the derivatives of f and g. \[\lim_{x\to c}\frac{f(x)}{g(x)}=\lim_{x\to c}\frac{f'(x)}{g'(x)}\] The quotient rule itself wasn't used because you do not find the derivative for f(x)/g(x), but rather f(x) and g(x) separately.

    • one year ago
  23. pottersheep Group Title
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    Ohhhhhhh thanks!!!

    • one year ago
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