## xartaan Group Title Find the directional derivative of $f(x,y,z) = yz + x^4$ at (2,3,1) in the direction of vector v=i+j+k. I have gotten as far as finding the directional derivative (gradient) at (2,3,1) which is: 32i+3j+k I dont know how to do the second part of this problem. What does it mean to find this direction? What do I have to do to the gradient to find it? My book is very vague, please help! one year ago one year ago

1. xartaan Group Title

Tips?

2. xartaan Group Title

The box for the answer says fu= _____ , where u looks like a unit vector, is that what this is asking for? A unit vector of the gradient?

3. xartaan Group Title

Never mind, that, I tried, and was told my answer should be a number, not a vector. Guess I misinterpreted that.

4. xartaan Group Title

5. UnkleRhaukus Group Title

$\newcommand \ve [1] { \mathbf{#1} }% vector \nabla_{\ve v}f(\ve x)=\nabla f(\ve x)\cdot{\ve v}\\ \ \\ f=yz+x^4\\ \ve v=(1,1,1)$

6. xartaan Group Title

I think I understand what you wrote, but it still isnt clear to me what "in the direction of" means... I can find the gradient just fine, I've just no idea what to do with it.

7. UnkleRhaukus Group Title

once you have found the gradient, take the dot product with the direction vector

8. xartaan Group Title

ahhhhh, that makes sense, thank you!