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anonymous
 3 years ago
What is a possible first step to eliminate a variable in the following system?
7x  9y = 2
3x  6y = 4
Choices
Multiply the first equation by 2 and the second equation by 3.
Multiply the first equation by 3 and the second equation by 2.
Multiply the first equation by 7 and the second equation by 3.
Multiply the first equation by 2 and the second equation by 4.
anonymous
 3 years ago
What is a possible first step to eliminate a variable in the following system? 7x  9y = 2 3x  6y = 4 Choices Multiply the first equation by 2 and the second equation by 3. Multiply the first equation by 3 and the second equation by 2. Multiply the first equation by 7 and the second equation by 3. Multiply the first equation by 2 and the second equation by 4.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0<<7x9y=2 <<3x6y=4 When doing elimination the idea is to get one of the variables to cancel out. 2(7x9y)=2(2) = 14x18y=4 [first equation] 3(3x6y)=3(4) = 9x+18y=12 [second equation] You'll notice that the y's in this case cancel each other out. Multiply the first equation by 2 and the second equation by 3

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1\(\color{goldenrod}{ 14x18y=4}\) [first equation] \(\color{cornflowerblue}{ 9x+18y=12}\) [second equation] Adding the equations\[\color{goldenrod}{(14x18y)}+\color{cornflowerblue}{(9x+18y)}=\color{goldenrod}{(4)}+\color{cornflowerblue}{(12)}\]\[(\color{goldenrod}{14}\color{cornflowerblue}{9})x+(\color{goldenrod}{18}+\color{cornflowerblue}{18})y=\color{goldenrod}{4}+\color{cornflowerblue}{12}\]\[(\color{seagreen}5)x+(\color{seagreen}0)y=\color{seagreen}{16}\]\[\color{seagreen}5x=\color{seagreen}{16}\] \[x={\frac{\color{seagreen}{16}}{\color{seagreen}5}}\]
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