Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Faman39

  • one year ago

Please help!

  • This Question is Closed
  1. Faman39
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

  2. Faman39
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @.Sam. can you able to help with this, please?

  3. Faman39
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Frostbite can you able to help me please?

  4. Faman39
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Callisto can you please?

  5. Faman39
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @RadEn @AriPotta @agent0smith can you guys please help me?

  6. Faman39
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @KonradZuse can you able to help me please?

  7. agent0smith
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Enter a few values of x, maybe -1, 0, 1, and calculate the corresponding y values. y = -3( ) + 5 Insert the x value into the brackets.

  8. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.