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DLSBest ResponseYou've already chosen the best response.0
Which carbo cation is least likely to form as as intermediate? dw:1360852772005:dw
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
A) is 3 degree and so is C)
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
B is 2 degree, also has a double bond which adds to the stability
 one year ago

DLSBest ResponseYou've already chosen the best response.0
its definitely not A for sure
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
C is attached to 3 carbons ?
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
hmm ? well still there are 3 carbons !
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
If i had to put a guess, I'd say D)
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
hmm,, sorry about that then! :
 one year ago

DLSBest ResponseYou've already chosen the best response.0
man I really thought u shud know all that before 2 months of JEE LOL
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
Wish your thinking was true!
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
Well I have never seen a bridged carbocation before.
 one year ago

DLSBest ResponseYou've already chosen the best response.0
are u freaking kidding me ._.
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
On a bridge head a positive carbon never occurs ~Wikipedia
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
http://en.wikibooks.org/wiki/Organic_Chemistry/Introduction_to_reactions/Carbocations
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
hmm, that is why it must be least likely to form! hmm, seems legit
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
well since bridged carbocation is not formed, hence it is least likely to be formed here.
 one year ago

DLSBest ResponseYou've already chosen the best response.0
i asked why it isnt form ._. i dont want to accept it as a fact
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
I don't know the fact! I just learnt it!
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
reason of the fact*
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
Here, you may read this, this has the reason http://www.tricity.wsu.edu/Chem540/ar00096a001.pdf
 one year ago

DLSBest ResponseYou've already chosen the best response.0
god i cant read that whole thing :/
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
learn as fact! thats what I just did !
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
In chem, most of times, there aren't reasons, there are rules, !
 one year ago

DLSBest ResponseYou've already chosen the best response.0
http://fc06.deviantart.net/fs70/f/2011/288/3/c/nothing_to_do_here_by_rober_raikd4cxltj.png
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
http://narwhaler.com/img/ys/x/iseeyourpointspearspidermanYsX3vo.jpg
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
Shuld nt the answer be D............
 one year ago

abb0tBest ResponseYou've already chosen the best response.0
If (A) is benzene, then it's (D). Remember you can't form primary carbocations ever.
 one year ago

DLSBest ResponseYou've already chosen the best response.0
but i want smt more detailed
 one year ago

abb0tBest ResponseYou've already chosen the best response.0
Wikipedia says the answer is C?
 one year ago

DLSBest ResponseYou've already chosen the best response.0
On a bridge head a positive carbon never occurs ~Wikipedia
 one year ago

abb0tBest ResponseYou've already chosen the best response.0
The + isn't on the bridge though.
 one year ago

DLSBest ResponseYou've already chosen the best response.0
that is why it cant resonate,the charge is localized.
 one year ago

DLSBest ResponseYou've already chosen the best response.0
so isnt C in a worse condition than D? it cant resonate at all but D still can
 one year ago

abb0tBest ResponseYou've already chosen the best response.0
Resonance is not the same as formation of a carbocation
 one year ago

DLSBest ResponseYou've already chosen the best response.0
its about the stability of the carbocation
 one year ago

abb0tBest ResponseYou've already chosen the best response.0
Resonance just tells you where electron behaves or forms a more stable structure
 one year ago

DLSBest ResponseYou've already chosen the best response.0
more resonating structures=more stable C h as 0 resonating structures
 one year ago

abb0tBest ResponseYou've already chosen the best response.0
Draw them for acetylene.
 one year ago

DLSBest ResponseYou've already chosen the best response.0
dw:1360961235810:dw not sure duh
 one year ago

abb0tBest ResponseYou've already chosen the best response.0
I don't think that would work. Did you move the hydrogen?????
 one year ago

abb0tBest ResponseYou've already chosen the best response.0
Resonance is only movement of the electron. Not protons.
 one year ago

abb0tBest ResponseYou've already chosen the best response.0
Maybe @BluFoot can help right now I'm not on my comp so I can't give detailed answers right now and don't have my notes w/ me. If you're on later I will explain better if no1 else has helped you. I gtg
 one year ago

BluFootBest ResponseYou've already chosen the best response.1
A is very stable because of all the resonance from the phenyl groups. B is kinda stable from the resonance of the double bond. This is called an "allylic carbocation" http://science.uvu.edu/ochem/index.php/alphabetical/ab/allyliccarbocation/ C has no resonance, but it's tertiary at least D is definitely the least stable. Vinylic carbocations (+ on the C=C) are reaalllllllyyyy unstable. The reason is based in orbitals. C=C are sp2, but with a carbocation it becomes sp. sp orbitals are situated close to the nucleus, so the positive charge is very close to the nucleus, which is positive, so it's unstable
 one year ago

BluFootBest ResponseYou've already chosen the best response.1
I've never seen the structure in C btw... do you know what it's called?
 one year ago

DLSBest ResponseYou've already chosen the best response.0
ive been taught its bridgehead carbon (out of the plane)
 one year ago

BluFootBest ResponseYou've already chosen the best response.1
Oh right, I haven't learned about those. It's still probably D but don't make my word for it since I know nothing about the bridges.
 one year ago

BluFootBest ResponseYou've already chosen the best response.1
I have no idea, sorry :/
 one year ago

abb0tBest ResponseYou've already chosen the best response.0
It's a bicyclo compound.
 one year ago

abb0tBest ResponseYou've already chosen the best response.0
Well, "C" would form a radical rather than a carbocation since it's an all hydrocarbon structure. That could be one argument. I'm not entirely sure about this one to be honest. But I can't help but also think the answer could be D since you don't usually ever have primary carbocations. And there's no type of resonance in structure D. If you take out the double bond, you'd have another charge and that would definitely form a very thermodynamically unstable structure. It would definitely prefer to stay.
 one year ago

aaronqBest ResponseYou've already chosen the best response.2
If the answer was to be C, then, i imagine that'd it would be because the strain put on it by it's inability to undergo an sp2 conformation (180 degree angles) since it's fixed on the frame and it would make of high energy/unstable
 one year ago
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