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stottrupbailey Group TitleBest ResponseYou've already chosen the best response.0
\[\int\limits_{}^{}\frac{ 6x }{ 2x+1 }dx\]
 one year ago

ZeHanz Group TitleBest ResponseYou've already chosen the best response.1
Try to rewrite the fraction: in the denominator, there is 2x+1. If you had that in the numerator as well, things would become easier. So, if it was: (6x+3)/(2x+1), this would be 3(2x+1)/(2x+1)=3. We cannot make it that simple, but we can go in the same direction:\[\int\limits_{}^{}\frac{ 6x }{ 2x+1 }dx=\int\limits_{}^{}\frac{ 6x+33 }{ 2x+1 }dx=\int\limits_{}^{}\frac{ 3(2x+1)3 }{ 2x+1 }dx\]Now we can split it up:\[=\int\limits_{}^{}3dx\int\limits_{}^{}\frac{ 3 }{ 2x+1 }dx\]Maybe you can try this yourself...
 one year ago

stottrupbailey Group TitleBest ResponseYou've already chosen the best response.0
ah, I see... never would've gotten that lol thanks so much! :)
 one year ago

ZeHanz Group TitleBest ResponseYou've already chosen the best response.1
BTW, although you said you'd never think of this yourself, next time you will!
 one year ago

stottrupbailey Group TitleBest ResponseYou've already chosen the best response.0
haha thanks :)
 one year ago
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