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anonymous
 3 years ago
A 5.5 kg bowling ball initially at rest is dropped from the top of a 12 m building. It hits the ground 1.75 s later. Find the net external force on the falling ball.
anonymous
 3 years ago
A 5.5 kg bowling ball initially at rest is dropped from the top of a 12 m building. It hits the ground 1.75 s later. Find the net external force on the falling ball.

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yrelhan4
 3 years ago
Best ResponseYou've already chosen the best response.1s=1/2at^2 you have s and t find a. net force=ma. plug and solve.

yrelhan4
 3 years ago
Best ResponseYou've already chosen the best response.1s>distance travelled a> acceleration due to gravity here t>time taken

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I 431.2N but that isn't an option..

yrelhan4
 3 years ago
Best ResponseYou've already chosen the best response.143.12 N is the answer.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So this is what I did.. s=12m a=? t=1.75s 12=((1.75)^2a)/2 12=(3.0625a)/2 24=3.0625a a=7.84 netforce=55*7.84 netforce=431.2N

yrelhan4
 3 years ago
Best ResponseYou've already chosen the best response.1Net acceleration. a = 2*12/1.75² Net force ma = 5.5* 2*12/1.75² = 43.12 N

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I get what your saying now. But the only problem is my choices are 120N, 54N, & 0N. But I can rule out 0N automatically

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Its okay, thanks for your help though :) I really do appreciate it

yrelhan4
 3 years ago
Best ResponseYou've already chosen the best response.1you're welcome. good luck. :)
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