anonymous
  • anonymous
A 5.5 kg bowling ball initially at rest is dropped from the top of a 12 m building. It hits the ground 1.75 s later. Find the net external force on the falling ball.
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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yrelhan4
  • yrelhan4
s=1/2at^2 you have s and t find a. net force=ma. plug and solve.
anonymous
  • anonymous
What is s?
yrelhan4
  • yrelhan4
s-->distance travelled a--> acceleration due to gravity here t-->time taken

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anonymous
  • anonymous
Okay, thanks:)
yrelhan4
  • yrelhan4
cheers!
anonymous
  • anonymous
I 431.2N but that isn't an option..
yrelhan4
  • yrelhan4
43.12 N is the answer.
anonymous
  • anonymous
So this is what I did.. s=12m a=? t=1.75s 12=((1.75)^2a)/2 12=(3.0625a)/2 24=3.0625a a=7.84 netforce=55*7.84 netforce=431.2N
yrelhan4
  • yrelhan4
Net acceleration. a = 2*12/1.75² Net force ma = 5.5* 2*12/1.75² = 43.12 N
anonymous
  • anonymous
I get what your saying now. But the only problem is my choices are 120N, 54N, & 0N. But I can rule out 0N automatically
yrelhan4
  • yrelhan4
hmm. no idea. sorry.
anonymous
  • anonymous
Its okay, thanks for your help though :) I really do appreciate it
yrelhan4
  • yrelhan4
you're welcome. good luck. :)

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