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A 5.5 kg bowling ball initially at rest is dropped from the top of a 12 m building. It hits the ground 1.75 s later. Find the net external force on the falling ball.
 one year ago
 one year ago
A 5.5 kg bowling ball initially at rest is dropped from the top of a 12 m building. It hits the ground 1.75 s later. Find the net external force on the falling ball.
 one year ago
 one year ago

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yrelhan4Best ResponseYou've already chosen the best response.1
s=1/2at^2 you have s and t find a. net force=ma. plug and solve.
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
s>distance travelled a> acceleration due to gravity here t>time taken
 one year ago

cutie.patootieBest ResponseYou've already chosen the best response.0
I 431.2N but that isn't an option..
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
43.12 N is the answer.
 one year ago

cutie.patootieBest ResponseYou've already chosen the best response.0
So this is what I did.. s=12m a=? t=1.75s 12=((1.75)^2a)/2 12=(3.0625a)/2 24=3.0625a a=7.84 netforce=55*7.84 netforce=431.2N
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
Net acceleration. a = 2*12/1.75² Net force ma = 5.5* 2*12/1.75² = 43.12 N
 one year ago

cutie.patootieBest ResponseYou've already chosen the best response.0
I get what your saying now. But the only problem is my choices are 120N, 54N, & 0N. But I can rule out 0N automatically
 one year ago

cutie.patootieBest ResponseYou've already chosen the best response.0
Its okay, thanks for your help though :) I really do appreciate it
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
you're welcome. good luck. :)
 one year ago
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