Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Rachel98 Group Title

Check three of my answers to three different problems? Question #1: Evaluate x-3 for x = 2 My answer: 1/8. Question #2: Simplify 2a0. My Answer: 2. Question #3: Simplify (5/9)^- 2. My Answer: So here we can use the negative to flip around the fraction. So once we flip it around we get (9/5)^2. So the negative is gone, but the two is still there. So now we we can solve this with 9/5 * 9/5. We can multiply straight across for the top and get 81, for the bottom we multiply straight across and get 25. So the answer is 81/25.

  • one year ago
  • one year ago

  • This Question is Closed
  1. phi Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yes, all three are correct. if you mean x^-3 (it looks like x-3 or 2-3= -1. you should put in the ^ to show the -3 is an exponent) 2^-3 is 1/2^3 = 1/(2*2*2)= 1/8 same for 2a^0 where a^0 is 1 (anything to the 0 power is 1, except for 0^0 which is not defined) your explanations #3 is excellent

    • one year ago
  2. Rachel98 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Thanks.

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.