## Shawna17 2 years ago Solve the equation on the interval [0, 2π). cos x + 2 cos x sin x = 0

1. Swaazy

2. Shawna17

ok then what?

3. Swaazy

4. ZeHanz

You should explain a little...

5. ZeHanz

(@Swaazy )

6. Swaazy

naaaaah

7. churrity

I like toast

8. ZeHanz

Try to factor: you can factor out cos x

9. ZeHanz

cos x(1+2sin x)=0

10. Swaazy

quit trippin . . .

11. churrity

ZeHanz = Afganistan PIMP

12. ZeHanz

So cos x = 0 or 1+2sin x = 0

13. Shawna17

ok

14. Swaazy

don't lie . . .

15. churrity

16. Shawna17

@Swaazy look i asked for help not someone to annoy me

17. Swaazy

and here comes your mother with those two little guys. Punched me in the belly and stepped on my feet, wauh slammed the bit* on the hard concrete

18. ZeHanz

cos x = 0 or sin x = -½ Now try to remember what values of x will give cos x = 0 or sin x = -½...

19. churrity

The pimp was strong, the bit*h was gone, something was wrong I said what is going on?

20. Shawna17

@Swaazy you are now block thanks have a nice life

21. Swaazy

yo

22. ZeHanz

@Shawna17: can you look up these values in a table?

23. Shawna17

how would I do that do you have a link?

24. ZeHanz

You could use this one, see image

25. Shawna17

my choices are A. 0, pi/2, 7pi/6, 3pi/2 B. pi/2, 7pi/6, 3pi/2,11pi/6 C 7pi/6, 11pi/6, 2pi D. 7pi/6, 11pi/6

26. ZeHanz

cos x = 0 gives pi/2 and 3pi/2 sin x = -½ gives 7pi/6 and 11pi/6

27. Shawna17

so it's B

28. ZeHanz

Yup!