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Solve the equation on the interval [0, 2π). cos x + 2 cos x sin x = 0

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ok then what?
thats the answer

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Other answers:

You should explain a little...
I like toast
Try to factor: you can factor out cos x
cos x(1+2sin x)=0
quit trippin . . .
ZeHanz = Afganistan PIMP
So cos x = 0 or 1+2sin x = 0
don't lie . . .
dry your eye
@Swaazy look i asked for help not someone to annoy me
and here comes your mother with those two little guys. Punched me in the belly and stepped on my feet, wauh slammed the bit* on the hard concrete
cos x = 0 or sin x = -½ Now try to remember what values of x will give cos x = 0 or sin x = -½...
The pimp was strong, the bit*h was gone, something was wrong I said what is going on?
@Swaazy you are now block thanks have a nice life
@Shawna17: can you look up these values in a table?
how would I do that do you have a link?
You could use this one, see image
1 Attachment
my choices are A. 0, pi/2, 7pi/6, 3pi/2 B. pi/2, 7pi/6, 3pi/2,11pi/6 C 7pi/6, 11pi/6, 2pi D. 7pi/6, 11pi/6
cos x = 0 gives pi/2 and 3pi/2 sin x = -½ gives 7pi/6 and 11pi/6
so it's B

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