Shawna17
Solve the equation on the interval [0, 2π). cos x + 2 cos x sin x = 0



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Swaazy
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Shawna17
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ok then what?

Swaazy
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thats the answer

ZeHanz
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You should explain a little...

ZeHanz
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(@Swaazy )

Swaazy
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naaaaah

churrity
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I like toast

ZeHanz
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Try to factor: you can factor out cos x

ZeHanz
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cos x(1+2sin x)=0

Swaazy
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quit trippin . . .

churrity
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ZeHanz = Afganistan PIMP

ZeHanz
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So cos x = 0 or 1+2sin x = 0

Shawna17
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ok

Swaazy
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don't lie . . .

churrity
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dry your eye

Shawna17
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@Swaazy look i asked for help not someone to annoy me

Swaazy
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and here comes your mother with those two little guys.
Punched me in the belly and stepped on my feet, wauh slammed the bit* on the hard concrete

ZeHanz
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cos x = 0 or sin x = ½
Now try to remember what values of x will give cos x = 0 or sin x = ½...

churrity
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The pimp was strong, the bit*h was gone, something was wrong I said what is going on?

Shawna17
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@Swaazy you are now block thanks have a nice life

Swaazy
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yo

ZeHanz
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@Shawna17: can you look up these values in a table?

Shawna17
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how would I do that do you have a link?

ZeHanz
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You could use this one, see image

Shawna17
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my choices are
A. 0, pi/2, 7pi/6, 3pi/2
B. pi/2, 7pi/6, 3pi/2,11pi/6
C 7pi/6, 11pi/6, 2pi
D. 7pi/6, 11pi/6

ZeHanz
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cos x = 0 gives pi/2 and 3pi/2
sin x = ½ gives 7pi/6 and 11pi/6

Shawna17
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so it's B

ZeHanz
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Yup!