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ursularoxursox

  • 3 years ago

Please help me out. I should be able to do the rest on my own once I see the steps to solve this problem. (64x^6)^(-5/3) I have to simplify

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  1. ZeHanz
    • 3 years ago
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    You need to know the basic rules of powers:\[a^{-b}=\frac{ 1 }{ a^b }\]\[a^{\frac{ ^b }{ c }} =\sqrt[c]{a^b}=(\sqrt[c]{a})^b\]\[(a^b)^c=a^{bc}\]\[a^b \cdot a^c=a^{b+c}\]\[\frac{ a^b }{ a^c }=a^{b-c}\] Try to see what you need to do with these rules here...

  2. ursularoxursox
    • 3 years ago
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    alright i did, thanks, this is what I got. \[\sqrt[5]{64x ^{26}}\]

  3. ursularoxursox
    • 3 years ago
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    5 root 64x^26 in case the other post was hard to read

  4. ZeHanz
    • 3 years ago
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    I got to: \[(64x^6)^{-\frac{ 5 }{ 3 }}=\frac{ 1 }{ (64x^6)^{\frac{ 5 }{ 3 } }}=\frac{ 1 }{ 64^{\frac{5}{3}}x^{6 \cdot \frac{5}{3}} }=\frac{ 1 }{64^{\frac{5}{3}} x^{10}}\]Now we have that nasy 64^(5/3)... But 64=2^6! so we can go a bit further:\[\frac{ 1 }{ (2^6)^{\frac{5}{3}} x^{10}}=\frac{ 1 }{ 2^{10}x^{10} }=\frac{ 1 }{ 1024x^{10} }\]

  5. ursularoxursox
    • 3 years ago
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    thank you so much! it makes sense. I just have to remember my exponent rules and factors :) thanks for your help!

  6. ZeHanz
    • 3 years ago
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    Once you've seen it again, you'll remember...just practise a few more and you're safe!

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