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Solve the equation. Check the solution.
2/(x+4) = 4/(x+3)
a. 13/6
b. 11
c. 8/3
d. 11/3
 one year ago
 one year ago
Solve the equation. Check the solution. 2/(x+4) = 4/(x+3) a. 13/6 b. 11 c. 8/3 d. 11/3
 one year ago
 one year ago

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ryanpaulsBest ResponseYou've already chosen the best response.0
also could you show your work? I am not sure how to do this because of the equal sign
 one year ago

ZeHanzBest ResponseYou've already chosen the best response.0
Use the rule:\[\frac{ a }{ b }=\frac{ c }{ d } \Leftrightarrow ad=bc\]so: 2((x+3)=4(x+4) expand the brackets, collect like terms and solve for x.
 one year ago

FibonacciChick666Best ResponseYou've already chosen the best response.1
so first relieve yourself of the fractions by multiplying the denominators on both sides and get: \[2/(x+4)=4/(x+3)\] \[2(x+3)=4(x+4)\] now distribute the 2,4 \[2x6=4x+16\] finally solve for x by combining like terms \[2x=4x+16+6\] \[6x=22\] \[x=22/6\] this reduces to \[x=11/3\] therefore our answer is d.
 one year ago

ryanpaulsBest ResponseYou've already chosen the best response.0
thanks! i just tried it out like that and I got the same answer.
 one year ago

FibonacciChick666Best ResponseYou've already chosen the best response.1
do you understand the process?
 one year ago

ryanpaulsBest ResponseYou've already chosen the best response.0
what about: Simplify the sum (x2)/(x+3) + (10x)/(x^29) I have this: (x2)/(x+3) + (10x)/(x+3)(x3) I know the x+4 cancels out, but what do I do to the top?
 one year ago

ryanpaulsBest ResponseYou've already chosen the best response.0
i meant x+3 cancels out
 one year ago

FibonacciChick666Best ResponseYou've already chosen the best response.1
ok so what you want to do is multiply the first fraction by a fraction that simplifies to 1. pick something that gives you the same denominator
 one year ago
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