anonymous
  • anonymous
Match the graphs of the functions on the left with the graphs of their derivatives on the right.
Mathematics
schrodinger
  • schrodinger
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

ZeHanz
  • ZeHanz
Do you know what the derivative of a 2nd degree function is?
anonymous
  • anonymous
no
ZeHanz
  • ZeHanz
You know the following I guess: If f is decreasing, then f' is negative (and vice versa). If f is increasing, then f' is positive ( and vv).
anonymous
  • anonymous
yes
ZeHanz
  • ZeHanz
No look at the first graph on the left. To the left of the y-axis, it is decreasing, to the right it is increasing.
anonymous
  • anonymous
yes it does
ZeHanz
  • ZeHanz
This means, for f' you are looking for a function that is negative on the left side of the y-axis and positive on the right.
anonymous
  • anonymous
ok
anonymous
  • anonymous
so it will be #2 in the second attachment?
ZeHanz
  • ZeHanz
I can see it on one of your drawings on the right! Do you?
anonymous
  • anonymous
Yes it will be number 2 ?
anonymous
  • anonymous
so to will have letter A
ZeHanz
  • ZeHanz
No, I've got C
anonymous
  • anonymous
but you can't match a with c , it says to match the left with the right so it has to be a letter with a number
ZeHanz
  • ZeHanz
I mean this (see image) The parabola on the left (2nd degree function) has the straight line on the right as it's derivative.
1 Attachment
anonymous
  • anonymous
so number one will be 1 with letter c?
anonymous
  • anonymous
I meant number 2 sorry
anonymous
  • anonymous
so 2C ?
ZeHanz
  • ZeHanz
Yes
anonymous
  • anonymous
okay
ZeHanz
  • ZeHanz
Now try #2. See what it does: increasing, decreasing, increasing. So you're looking for a graph that is +, then -, then +.
anonymous
  • anonymous
i thought we already did number 2
anonymous
  • anonymous
?
zepdrix
  • zepdrix
He was telling you number #1 is C. There musta been some confusion there c:
anonymous
  • anonymous
ohhh okay lol sorry
anonymous
  • anonymous
so number 2 will be f?
ZeHanz
  • ZeHanz
@zepdrix: thx
ZeHanz
  • ZeHanz
Yes!
anonymous
  • anonymous
okay :)
ZeHanz
  • ZeHanz
I think you got it!
anonymous
  • anonymous
number 3 looks funny
zepdrix
  • zepdrix
I think #2 is `e` actually :o hmm
ZeHanz
  • ZeHanz
It is down, up, down, up, so look for -,+,-,+
anonymous
  • anonymous
okay so number 3 will be A ?
ZeHanz
  • ZeHanz
@zepdrix : you're right, I'm having trouble looking at three different pictures, @onegirl: sorry ;)
anonymous
  • anonymous
okay thanks for the correction zep
anonymous
  • anonymous
so 3A ?
ZeHanz
  • ZeHanz
Yes, 3A
anonymous
  • anonymous
okay
anonymous
  • anonymous
so number 4 will be D?
ZeHanz
  • ZeHanz
Right again! Always decreasing, so looking for a derivative that is always negative...
anonymous
  • anonymous
okay
anonymous
  • anonymous
so i'm guessing number 5 will be 5B?
anonymous
  • anonymous
?
ZeHanz
  • ZeHanz
You guessed wrong... Look at graph #5 and compare with #3
ZeHanz
  • ZeHanz
It behaves in the same way: dec, inc, dec, inc, so -,+,-,+
anonymous
  • anonymous
ok so it will be 5f
ZeHanz
  • ZeHanz
Oops, look something went wrong with my last response. Because 5 and 3 behave in the same way, you have to choose the same derivative: 5A
anonymous
  • anonymous
ohh ok
anonymous
  • anonymous
so letter A goes to two graphs? okay
ZeHanz
  • ZeHanz
That's the mean part of the question ;)
anonymous
  • anonymous
okay so how about the last one number 6?
ZeHanz
  • ZeHanz
It goes down, then up, then down, so for f' we have: neg, pos, neg
anonymous
  • anonymous
so it will be 6B
ZeHanz
  • ZeHanz
No, that goes a lot more from - to + etc.
ZeHanz
  • ZeHanz
(it is really simple)
anonymous
  • anonymous
ohh so it will f since it does go negative pos then neg
ZeHanz
  • ZeHanz
Yes, it's 6F. I must admit this kind of question can be confusing, because you constantly have to switch from increasing , decreasing to +, -.
anonymous
  • anonymous
okay well thanks for your help

Looking for something else?

Not the answer you are looking for? Search for more explanations.