Match the graphs of the functions on the left with the graphs of their derivatives on the right.

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- anonymous

Match the graphs of the functions on the left with the graphs of their derivatives on the right.

- schrodinger

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- anonymous

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- anonymous

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- anonymous

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- ZeHanz

Do you know what the derivative of a 2nd degree function is?

- anonymous

no

- ZeHanz

You know the following I guess:
If f is decreasing, then f' is negative (and vice versa).
If f is increasing, then f' is positive ( and vv).

- anonymous

yes

- ZeHanz

No look at the first graph on the left.
To the left of the y-axis, it is decreasing, to the right it is increasing.

- anonymous

yes it does

- ZeHanz

This means, for f' you are looking for a function that is negative on the left side of the y-axis and positive on the right.

- anonymous

ok

- anonymous

so it will be #2 in the second attachment?

- ZeHanz

I can see it on one of your drawings on the right! Do you?

- anonymous

Yes it will be number 2 ?

- anonymous

so to will have letter A

- ZeHanz

No, I've got C

- anonymous

but you can't match a with c , it says to match the left with the right so it has to be a letter with a number

- ZeHanz

I mean this (see image)
The parabola on the left (2nd degree function) has the straight line on the right as it's derivative.

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- anonymous

so number one will be 1 with letter c?

- anonymous

I meant number 2 sorry

- anonymous

so 2C ?

- ZeHanz

Yes

- anonymous

okay

- ZeHanz

Now try #2.
See what it does: increasing, decreasing, increasing.
So you're looking for a graph that is +, then -, then +.

- anonymous

i thought we already did number 2

- anonymous

?

- zepdrix

He was telling you number #1 is C. There musta been some confusion there c:

- anonymous

ohhh okay lol sorry

- anonymous

so number 2 will be f?

- ZeHanz

@zepdrix: thx

- ZeHanz

Yes!

- anonymous

okay :)

- ZeHanz

I think you got it!

- anonymous

number 3 looks funny

- zepdrix

I think #2 is `e` actually :o hmm

- ZeHanz

It is down, up, down, up, so look for -,+,-,+

- anonymous

okay so number 3 will be A ?

- anonymous

okay thanks for the correction zep

- anonymous

so 3A ?

- ZeHanz

Yes, 3A

- anonymous

okay

- anonymous

so number 4 will be D?

- ZeHanz

Right again! Always decreasing, so looking for a derivative that is always negative...

- anonymous

okay

- anonymous

so i'm guessing number 5 will be 5B?

- anonymous

?

- ZeHanz

You guessed wrong...
Look at graph #5 and compare with #3

- ZeHanz

It behaves in the same way: dec, inc, dec, inc, so -,+,-,+

- anonymous

ok so it will be 5f

- ZeHanz

Oops, look something went wrong with my last response.
Because 5 and 3 behave in the same way, you have to choose the same derivative: 5A

- anonymous

ohh ok

- anonymous

so letter A goes to two graphs? okay

- ZeHanz

That's the mean part of the question ;)

- anonymous

okay so how about the last one number 6?

- ZeHanz

It goes down, then up, then down, so for f' we have: neg, pos, neg

- anonymous

so it will be 6B

- ZeHanz

No, that goes a lot more from - to + etc.

- ZeHanz

(it is really simple)

- anonymous

ohh so it will f since it does go negative pos then neg

- ZeHanz

Yes, it's 6F.
I must admit this kind of question can be confusing, because you constantly have to switch from increasing , decreasing to +, -.

- anonymous

okay well thanks for your help

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