waheguru
Can someone help me solve this
(x+2)^2 = 11^2+4^2
I want to solve it by expanding the (x+2)^2
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hartnn
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so, can you expand (x+2)^2 ?
waheguru
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yes it becomes
x^2+4x+4
hartnn
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x^2+4x+4 = 11^2+4^2
whats 11^2+4^2 =... ?
waheguru
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137
waheguru
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x^2+4x = 133
waheguru
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but what now from here ?
hartnn
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x^2 +4x -133 =0
do you know how to solve quadratic equations ?
waheguru
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no
hartnn
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Compare your quadratic equation with \(ax^2+bx+c=0\)
find \[a=...?\\b=...?\\c=...?\]
then the two roots of x are:
\(\huge{x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)
waheguru
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Thanks,
hartnn
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ok, welcome :)
you can ask if you get stuck while getting the values of x