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waheguru
Group Title
Can someone help me solve this
(x+2)^2 = 11^2+4^2
I want to solve it by expanding the (x+2)^2
 one year ago
 one year ago
waheguru Group Title
Can someone help me solve this (x+2)^2 = 11^2+4^2 I want to solve it by expanding the (x+2)^2
 one year ago
 one year ago

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hartnn Group TitleBest ResponseYou've already chosen the best response.2
so, can you expand (x+2)^2 ?
 one year ago

waheguru Group TitleBest ResponseYou've already chosen the best response.0
yes it becomes x^2+4x+4
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
x^2+4x+4 = 11^2+4^2 whats 11^2+4^2 =... ?
 one year ago

waheguru Group TitleBest ResponseYou've already chosen the best response.0
x^2+4x = 133
 one year ago

waheguru Group TitleBest ResponseYou've already chosen the best response.0
but what now from here ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
x^2 +4x 133 =0 do you know how to solve quadratic equations ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
Compare your quadratic equation with \(ax^2+bx+c=0\) find \[a=...?\\b=...?\\c=...?\] then the two roots of x are: \(\huge{x_{1,2}=\frac{b \pm \sqrt{b^24ac}}{2a}}\)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
ok, welcome :) you can ask if you get stuck while getting the values of x
 one year ago
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