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waheguru
 3 years ago
Can someone help me solve this
(x+2)^2 = 11^2+4^2
I want to solve it by expanding the (x+2)^2
waheguru
 3 years ago
Can someone help me solve this (x+2)^2 = 11^2+4^2 I want to solve it by expanding the (x+2)^2

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hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2so, can you expand (x+2)^2 ?

waheguru
 3 years ago
Best ResponseYou've already chosen the best response.0yes it becomes x^2+4x+4

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2x^2+4x+4 = 11^2+4^2 whats 11^2+4^2 =... ?

waheguru
 3 years ago
Best ResponseYou've already chosen the best response.0but what now from here ?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2x^2 +4x 133 =0 do you know how to solve quadratic equations ?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2Compare your quadratic equation with \(ax^2+bx+c=0\) find \[a=...?\\b=...?\\c=...?\] then the two roots of x are: \(\huge{x_{1,2}=\frac{b \pm \sqrt{b^24ac}}{2a}}\)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2ok, welcome :) you can ask if you get stuck while getting the values of x
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