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waheguru

  • 3 years ago

Can someone help me solve this (x+2)^2 = 11^2+4^2 I want to solve it by expanding the (x+2)^2

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  1. hartnn
    • 3 years ago
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    so, can you expand (x+2)^2 ?

  2. waheguru
    • 3 years ago
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    yes it becomes x^2+4x+4

  3. hartnn
    • 3 years ago
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    x^2+4x+4 = 11^2+4^2 whats 11^2+4^2 =... ?

  4. waheguru
    • 3 years ago
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    137

  5. waheguru
    • 3 years ago
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    x^2+4x = 133

  6. waheguru
    • 3 years ago
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    but what now from here ?

  7. hartnn
    • 3 years ago
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    x^2 +4x -133 =0 do you know how to solve quadratic equations ?

  8. waheguru
    • 3 years ago
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    no

  9. hartnn
    • 3 years ago
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    Compare your quadratic equation with \(ax^2+bx+c=0\) find \[a=...?\\b=...?\\c=...?\] then the two roots of x are: \(\huge{x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)

  10. waheguru
    • 3 years ago
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    Thanks,

  11. hartnn
    • 3 years ago
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    ok, welcome :) you can ask if you get stuck while getting the values of x

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