waheguru Group Title Can someone help me solve this (x+2)^2 = 11^2+4^2 I want to solve it by expanding the (x+2)^2 one year ago one year ago

1. hartnn Group Title

so, can you expand (x+2)^2 ?

2. waheguru Group Title

yes it becomes x^2+4x+4

3. hartnn Group Title

x^2+4x+4 = 11^2+4^2 whats 11^2+4^2 =... ?

4. waheguru Group Title

137

5. waheguru Group Title

x^2+4x = 133

6. waheguru Group Title

but what now from here ?

7. hartnn Group Title

x^2 +4x -133 =0 do you know how to solve quadratic equations ?

8. waheguru Group Title

no

9. hartnn Group Title

Compare your quadratic equation with $$ax^2+bx+c=0$$ find $a=...?\\b=...?\\c=...?$ then the two roots of x are: $$\huge{x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}$$

10. waheguru Group Title

Thanks,

11. hartnn Group Title

ok, welcome :) you can ask if you get stuck while getting the values of x