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## waheguru 2 years ago Can someone help me solve this (x+2)^2 = 11^2+4^2 I want to solve it by expanding the (x+2)^2

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1. hartnn

so, can you expand (x+2)^2 ?

2. waheguru

yes it becomes x^2+4x+4

3. hartnn

x^2+4x+4 = 11^2+4^2 whats 11^2+4^2 =... ?

4. waheguru

137

5. waheguru

x^2+4x = 133

6. waheguru

but what now from here ?

7. hartnn

x^2 +4x -133 =0 do you know how to solve quadratic equations ?

8. waheguru

no

9. hartnn

Compare your quadratic equation with $$ax^2+bx+c=0$$ find $a=...?\\b=...?\\c=...?$ then the two roots of x are: $$\huge{x_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}$$

10. waheguru

Thanks,

11. hartnn

ok, welcome :) you can ask if you get stuck while getting the values of x

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