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JenniferSmart1
 one year ago
Best ResponseYou've already chosen the best response.0dw:1360883013269:dw

JenniferSmart1
 one year ago
Best ResponseYou've already chosen the best response.0I guess I can get as far as doing the phase shift but I don't know what to do with the 2 in front of the x \[y=sin(2(x\pi/2))\]dw:1360883459233:dw

JenniferSmart1
 one year ago
Best ResponseYou've already chosen the best response.0the phase shift is pi/2 isn't it?

TuringTest
 one year ago
Best ResponseYou've already chosen the best response.1\[\sin(\pi)=0\]so the graph should start at x=0, y=0

JenniferSmart1
 one year ago
Best ResponseYou've already chosen the best response.0what does the phase shift do then?

TuringTest
 one year ago
Best ResponseYou've already chosen the best response.1a phase shift of pi will shift the graph a halfperiod to the right, which for the sin is equivalent to turning it upsidedown

JenniferSmart1
 one year ago
Best ResponseYou've already chosen the best response.0Oh i see. so the phase shift is pi and not pi/2

TuringTest
 one year ago
Best ResponseYou've already chosen the best response.1right, you could also see that by applying\[\sin(\alpha+\beta)=\sin\alpha\cos\beta+\cos\alpha\sin\beta\]

JenniferSmart1
 one year ago
Best ResponseYou've already chosen the best response.0makes sense. Thanks!
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