JenniferSmart1
graphing \[y=sin(2x\pi)\] did I graph this correctly?



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JenniferSmart1
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dw:1360883013269:dw

JenniferSmart1
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I guess I can get as far as doing the phase shift but I don't know what to do with the 2 in front of the x
\[y=sin(2(x\pi/2))\]dw:1360883459233:dw

JenniferSmart1
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@TuringTest

JenniferSmart1
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the phase shift is pi/2 isn't it?

TuringTest
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\[\sin(\pi)=0\]so the graph should start at x=0, y=0

JenniferSmart1
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what does the phase shift do then?

JenniferSmart1
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oh I see

JenniferSmart1
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no not really


TuringTest
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a phase shift of pi will shift the graph a halfperiod to the right, which for the sin is equivalent to turning it upsidedown

JenniferSmart1
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Oh i see. so the phase shift is pi and not pi/2

TuringTest
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right, you could also see that by applying\[\sin(\alpha+\beta)=\sin\alpha\cos\beta+\cos\alpha\sin\beta\]

JenniferSmart1
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makes sense. Thanks!

TuringTest
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welcome :D