A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

JenniferSmart1
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1360883013269:dw

JenniferSmart1
 2 years ago
Best ResponseYou've already chosen the best response.0I guess I can get as far as doing the phase shift but I don't know what to do with the 2 in front of the x \[y=sin(2(x\pi/2))\]dw:1360883459233:dw

JenniferSmart1
 2 years ago
Best ResponseYou've already chosen the best response.0the phase shift is pi/2 isn't it?

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1\[\sin(\pi)=0\]so the graph should start at x=0, y=0

JenniferSmart1
 2 years ago
Best ResponseYou've already chosen the best response.0what does the phase shift do then?

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1a phase shift of pi will shift the graph a halfperiod to the right, which for the sin is equivalent to turning it upsidedown

JenniferSmart1
 2 years ago
Best ResponseYou've already chosen the best response.0Oh i see. so the phase shift is pi and not pi/2

TuringTest
 2 years ago
Best ResponseYou've already chosen the best response.1right, you could also see that by applying\[\sin(\alpha+\beta)=\sin\alpha\cos\beta+\cos\alpha\sin\beta\]

JenniferSmart1
 2 years ago
Best ResponseYou've already chosen the best response.0makes sense. Thanks!
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.