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anonymous
 3 years ago
A rectangular pasture has a fence around the perimeter. The length of the fence is 16x7 and the width is 48x4. What is the area of the pasture? (1 point)
a) 3x^3
b)128x^11
c)768x^11
d)768x^28
I KNOW the answer is c, but i need it explained. I already found it here once but can ANYONE explain how to do this?
anonymous
 3 years ago
A rectangular pasture has a fence around the perimeter. The length of the fence is 16x7 and the width is 48x4. What is the area of the pasture? (1 point) a) 3x^3 b)128x^11 c)768x^11 d)768x^28 I KNOW the answer is c, but i need it explained. I already found it here once but can ANYONE explain how to do this?

This Question is Closed

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1Area of rectangular (here pasture) = Length * Width

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Allright, so how do i do it? 16 * ^7 gives nothing and im so confused How do i do 16x^7 * 48x^4? I dont get this problem

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Same thing with this > Simplify. 5^–1(3^–2) If i type this into a calculator i get a stupid number

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1ok, treat constants and variables separately. \(16x^7 \times 48x^4 = (16\times 48) \times(x^7 \times x^4)\) got this ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay... yes i think i get that... but where did the two Z come from

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1Z ?? there are no Z's there....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Whoops, sorry, okay, go on. I understand now

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I think i get it 16 * 48 = 768 And 7 + 4 = 11?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1actually, its \(x^7 \times x^4 = x^{7+4}=x^{11}\) and sure :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay something like this Simplify (4xy2)3(xy)5 and (sorry) this Evaluate a–4b2 for a = –2 and b = 4

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Simplify (4xy^2)^3(xy)^5 Sorry

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1i believe the first one looks like this : \((4xy^2)^3(xy)^5\)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1ok, so you need to remember/understand few thing before u start: \(\huge (ab)^n = a^nb^n\) and \(\huge (a^m)^n=a^{mn}\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The other problem i can't figure out how to write an equation

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1\(\large Evaluate \: \: a^{–4}b^2 \:\: for\:\: a = –2 \:\:and\:\: b = 4\) right ?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1ok, for the previous one : using, \(\huge (ab)^n = a^nb^n\) \(\large (4xy^2)^3= 4^3 x^3 (y^2)^3\) got this ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Are you doing Simplify (4xy^2)^3(xy)^5 ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0And you changed that to (4xy^2)^3=4^3x^3(y^2)^3....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0How did you do that... that hurts my brain

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1open up your brain and try to accept new things :)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1basically the exponent outside the bracket becomes the exponent of each of the terms inside the bracket.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Where did averything after that equal sign come from? Where'd the 5 go?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Howd 4 and the 4 more exponents come from

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1(4xy^2)^3(xy)^5 <you are asking about this 5 ? i am starting with (4xy^2)^3 part of (4xy^2)^3(xy)^5

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1if you are asking from where does all the exponents come from take a look at this again : \((ab)^n=a^nb^n\) or perhaps : \((abc)^n=a^nb^nc^n\)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1so i assume you are clear with this diagram.dw:1360892207194:dw using same rule, can you tell me what u get for \((xy)^5\) ??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360892393038:dw

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1correct :) see, it isn't difficult at all. now you have \(\large 4^3x^3(y^2)^3x^5y^5\) right ? lets start simplifying with constants (numbers) 4^3 =... ?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1yes. now comes the 2nd rule i posted. \(\huge (a^m)^n=a^{mn}\) so, what about \((y^2)^3\) ??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360892627948:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360892663950:dw

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1umm..no, let me give you an example \(\large (z^5)^3 = z^{5 \times 3 }=z^{15}\) do similar thing for \((y^2)^3 \)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1:O the exponents are getting multiplied. what are the 2 exponents in \((y^2)^3\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Its a 3 isnt it... Sorry (y^6)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1yes, y^6 is correct. so, we have now \(64x^3y^6x^5y^5\) lets bring 'x' terms and y terms together.

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1\(64 \: \: (x^3x^5) \:\: (y^6y^5)\) ok, any doubts ?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1now one of the very important rule : \(\large a^m a^n = a^{m+n}\) here, if we multiply the variables, their exponents gets ADDED . so, what about \(x^3x^5=... ?\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It would end up being 64(x^8)(y^11) ?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1wow! thats absolutely correct! :)
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