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A rectangular pasture has a fence around the perimeter. The length of the fence is 16x7 and the width is 48x4. What is the area of the pasture? (1 point)
a) 3x^3
b)128x^11
c)768x^11
d)768x^28
I KNOW the answer is c, but i need it explained. I already found it here once but can ANYONE explain how to do this?
 one year ago
 one year ago
A rectangular pasture has a fence around the perimeter. The length of the fence is 16x7 and the width is 48x4. What is the area of the pasture? (1 point) a) 3x^3 b)128x^11 c)768x^11 d)768x^28 I KNOW the answer is c, but i need it explained. I already found it here once but can ANYONE explain how to do this?
 one year ago
 one year ago

This Question is Closed

hartnnBest ResponseYou've already chosen the best response.1
Area of rectangular (here pasture) = Length * Width
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
Allright, so how do i do it? 16 * ^7 gives nothing and im so confused How do i do 16x^7 * 48x^4? I dont get this problem
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
Same thing with this > Simplify. 5^–1(3^–2) If i type this into a calculator i get a stupid number
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
ok, treat constants and variables separately. \(16x^7 \times 48x^4 = (16\times 48) \times(x^7 \times x^4)\) got this ?
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
Okay... yes i think i get that... but where did the two Z come from
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
Z ?? there are no Z's there....
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
Whoops, sorry, okay, go on. I understand now
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
I think i get it 16 * 48 = 768 And 7 + 4 = 11?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
actually, its \(x^7 \times x^4 = x^{7+4}=x^{11}\) and sure :)
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
Okay something like this Simplify (4xy2)3(xy)5 and (sorry) this Evaluate a–4b2 for a = –2 and b = 4
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
Simplify (4xy^2)^3(xy)^5 Sorry
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
i believe the first one looks like this : \((4xy^2)^3(xy)^5\)
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
ok, so you need to remember/understand few thing before u start: \(\huge (ab)^n = a^nb^n\) and \(\huge (a^m)^n=a^{mn}\)
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
The other problem i can't figure out how to write an equation
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
\(\large Evaluate \: \: a^{–4}b^2 \:\: for\:\: a = –2 \:\:and\:\: b = 4\) right ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
ok, for the previous one : using, \(\huge (ab)^n = a^nb^n\) \(\large (4xy^2)^3= 4^3 x^3 (y^2)^3\) got this ?
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
Oh man. So confused
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
Are you doing Simplify (4xy^2)^3(xy)^5 ?
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
And you changed that to (4xy^2)^3=4^3x^3(y^2)^3....
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
How did you do that... that hurts my brain
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
open up your brain and try to accept new things :)
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
basically the exponent outside the bracket becomes the exponent of each of the terms inside the bracket.
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
Where did averything after that equal sign come from? Where'd the 5 go?
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
Howd 4 and the 4 more exponents come from
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
(4xy^2)^3(xy)^5 <you are asking about this 5 ? i am starting with (4xy^2)^3 part of (4xy^2)^3(xy)^5
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
if you are asking from where does all the exponents come from take a look at this again : \((ab)^n=a^nb^n\) or perhaps : \((abc)^n=a^nb^nc^n\)
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
OHHHHHHHHHHHHHHHHHH
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
Yes, yes, go on (:
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
so i assume you are clear with this diagram.dw:1360892207194:dw using same rule, can you tell me what u get for \((xy)^5\) ??
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
dw:1360892393038:dw
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
correct :) see, it isn't difficult at all. now you have \(\large 4^3x^3(y^2)^3x^5y^5\) right ? lets start simplifying with constants (numbers) 4^3 =... ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
yes. now comes the 2nd rule i posted. \(\huge (a^m)^n=a^{mn}\) so, what about \((y^2)^3\) ??
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
dw:1360892627948:dw
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
dw:1360892663950:dw
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
umm..no, let me give you an example \(\large (z^5)^3 = z^{5 \times 3 }=z^{15}\) do similar thing for \((y^2)^3 \)
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
:O the exponents are getting multiplied. what are the 2 exponents in \((y^2)^3\)
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
Its a 3 isnt it... Sorry (y^6)
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
yes, y^6 is correct. so, we have now \(64x^3y^6x^5y^5\) lets bring 'x' terms and y terms together.
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
\(64 \: \: (x^3x^5) \:\: (y^6y^5)\) ok, any doubts ?
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
No, i got it so far.
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
now one of the very important rule : \(\large a^m a^n = a^{m+n}\) here, if we multiply the variables, their exponents gets ADDED . so, what about \(x^3x^5=... ?\)
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
It would end up being 64(x^8)(y^11) ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
wow! thats absolutely correct! :)
 one year ago

HatSimulatorBest ResponseYou've already chosen the best response.0
Thank you very much!
 one year ago
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