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 one year ago
A rectangular pasture has a fence around the perimeter. The length of the fence is 16x7 and the width is 48x4. What is the area of the pasture? (1 point)
a) 3x^3
b)128x^11
c)768x^11
d)768x^28
I KNOW the answer is c, but i need it explained. I already found it here once but can ANYONE explain how to do this?
 one year ago
A rectangular pasture has a fence around the perimeter. The length of the fence is 16x7 and the width is 48x4. What is the area of the pasture? (1 point) a) 3x^3 b)128x^11 c)768x^11 d)768x^28 I KNOW the answer is c, but i need it explained. I already found it here once but can ANYONE explain how to do this?

This Question is Closed

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1Area of rectangular (here pasture) = Length * Width

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0Allright, so how do i do it? 16 * ^7 gives nothing and im so confused How do i do 16x^7 * 48x^4? I dont get this problem

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0Same thing with this > Simplify. 5^–1(3^–2) If i type this into a calculator i get a stupid number

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1ok, treat constants and variables separately. \(16x^7 \times 48x^4 = (16\times 48) \times(x^7 \times x^4)\) got this ?

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0Okay... yes i think i get that... but where did the two Z come from

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1Z ?? there are no Z's there....

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0Whoops, sorry, okay, go on. I understand now

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0I think i get it 16 * 48 = 768 And 7 + 4 = 11?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1actually, its \(x^7 \times x^4 = x^{7+4}=x^{11}\) and sure :)

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0Okay something like this Simplify (4xy2)3(xy)5 and (sorry) this Evaluate a–4b2 for a = –2 and b = 4

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0Simplify (4xy^2)^3(xy)^5 Sorry

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1i believe the first one looks like this : \((4xy^2)^3(xy)^5\)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1ok, so you need to remember/understand few thing before u start: \(\huge (ab)^n = a^nb^n\) and \(\huge (a^m)^n=a^{mn}\)

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0The other problem i can't figure out how to write an equation

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1\(\large Evaluate \: \: a^{–4}b^2 \:\: for\:\: a = –2 \:\:and\:\: b = 4\) right ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1ok, for the previous one : using, \(\huge (ab)^n = a^nb^n\) \(\large (4xy^2)^3= 4^3 x^3 (y^2)^3\) got this ?

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0Oh man. So confused

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0Are you doing Simplify (4xy^2)^3(xy)^5 ?

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0And you changed that to (4xy^2)^3=4^3x^3(y^2)^3....

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0How did you do that... that hurts my brain

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1open up your brain and try to accept new things :)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1basically the exponent outside the bracket becomes the exponent of each of the terms inside the bracket.

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0Where did averything after that equal sign come from? Where'd the 5 go?

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0Howd 4 and the 4 more exponents come from

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1(4xy^2)^3(xy)^5 <you are asking about this 5 ? i am starting with (4xy^2)^3 part of (4xy^2)^3(xy)^5

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1if you are asking from where does all the exponents come from take a look at this again : \((ab)^n=a^nb^n\) or perhaps : \((abc)^n=a^nb^nc^n\)

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0OHHHHHHHHHHHHHHHHHH

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0Yes, yes, go on (:

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1so i assume you are clear with this diagram.dw:1360892207194:dw using same rule, can you tell me what u get for \((xy)^5\) ??

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0dw:1360892393038:dw

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1correct :) see, it isn't difficult at all. now you have \(\large 4^3x^3(y^2)^3x^5y^5\) right ? lets start simplifying with constants (numbers) 4^3 =... ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1yes. now comes the 2nd rule i posted. \(\huge (a^m)^n=a^{mn}\) so, what about \((y^2)^3\) ??

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0dw:1360892627948:dw

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0dw:1360892663950:dw

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1umm..no, let me give you an example \(\large (z^5)^3 = z^{5 \times 3 }=z^{15}\) do similar thing for \((y^2)^3 \)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1:O the exponents are getting multiplied. what are the 2 exponents in \((y^2)^3\)

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0Its a 3 isnt it... Sorry (y^6)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1yes, y^6 is correct. so, we have now \(64x^3y^6x^5y^5\) lets bring 'x' terms and y terms together.

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1\(64 \: \: (x^3x^5) \:\: (y^6y^5)\) ok, any doubts ?

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0No, i got it so far.

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1now one of the very important rule : \(\large a^m a^n = a^{m+n}\) here, if we multiply the variables, their exponents gets ADDED . so, what about \(x^3x^5=... ?\)

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0It would end up being 64(x^8)(y^11) ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1wow! thats absolutely correct! :)

HatSimulator
 one year ago
Best ResponseYou've already chosen the best response.0Thank you very much!
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