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Area of rectangular (here pasture) = Length * Width

Same thing with this > Simplify. 5^–1(3^–2)
If i type this into a calculator i get a stupid number

Okay... yes i think i get that... but where did the two Z come from

Z ?? there are no Z's there....

Whoops, sorry, okay, go on. I understand now

I think i get it
16 * 48 = 768
And 7 + 4 = 11?

good!

Okay, 1 more?

actually, its \(x^7 \times x^4 = x^{7+4}=x^{11}\)
and sure :)

Okay
something like this
Simplify (4xy2)3(xy)5
and (sorry) this
Evaluate a–4b2 for a = –2 and b = 4

Simplify (4xy^2)^3(xy)^5
Sorry

i believe the first one looks like this :
\((4xy^2)^3(xy)^5\)

okay

The other problem i can't figure out how to write an equation

\(\large Evaluate \: \: a^{–4}b^2 \:\: for\:\: a = –2 \:\:and\:\: b = 4\)
right ?

Oh man. So confused

Are you doing Simplify (4xy^2)^3(xy)^5 ?

yes.

And you changed that to (4xy^2)^3=4^3x^3(y^2)^3....

How did you do that... that hurts my brain

|dw:1360891677558:dw|

open up your brain and try to accept new things :)

Where did averything after that equal sign come from? Where'd the 5 go?

Howd 4 and the 4 more exponents come from

OHHHHHHHHHHHHHHHHHH

Yes, yes, go on (:

|dw:1360892393038:dw|

64

yes.
now comes the 2nd rule i posted.
\(\huge (a^m)^n=a^{mn}\)
so, what about \((y^2)^3\) ??

|dw:1360892627948:dw|

12? how ?

Wait

|dw:1360892663950:dw|

y^1*2

(y^2)

:O
the exponents are getting multiplied.
what are the 2 exponents in \((y^2)^3\)

Its a 3 isnt it... Sorry
(y^6)

yes, y^6 is correct.
so, we have now
\(64x^3y^6x^5y^5\)
lets bring 'x' terms and y terms together.

\(64 \: \: (x^3x^5) \:\: (y^6y^5)\)
ok, any doubts ?

No, i got it so far.

It would end up being 64(x^8)(y^11) ?

Thats the answer

wow! thats absolutely correct! :)

did you get how ?

Yep!

I get it now

Thank you very much!

welcome ^_^