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ksaimouli
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\[\frac{ x^2 }{ 2 }\cos2x+\frac{ x }{ 2 }\sin2x+\frac{ 1 }{ 4 }\cos 2x\]

ksaimouli
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to dw:1360893059171:dw

ksaimouli
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i tried this i got \[\frac{ \pi^2 }{ 8 }\frac{ 1 }{ 4 }\]

hartnn
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how u got that ? show your work, i'll spot the error.

ksaimouli
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oka

ksaimouli
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dw:1360893431147:dw

ksaimouli
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step 1 is that right

hartnn
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yes.

ksaimouli
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okay step 2dw:1360893564991:dw

hartnn
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what about the lower limit of 0, will that come later ?

hartnn
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so, you got pi^2/81/4 only by substituting upper limit ?

hartnn
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thats correct by the way, but incomplete

ksaimouli
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shut i forgot that literally i thought no value in polynomials but their is a value for trig

ksaimouli
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ya i found the mistake thx

hartnn
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yes, cos 0 is not 0

hartnn
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welcome ^_^