ksaimouli
  • ksaimouli
evaluate
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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ksaimouli
  • ksaimouli
\[\frac{ -x^2 }{ 2 }\cos2x+\frac{ x }{ 2 }\sin2x+\frac{ 1 }{ 4 }\cos 2x\]
ksaimouli
  • ksaimouli
to |dw:1360893059171:dw|
ksaimouli
  • ksaimouli
i tried this i got \[\frac{ \pi^2 }{ 8 }-\frac{ 1 }{ 4 }\]

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hartnn
  • hartnn
how u got that ? show your work, i'll spot the error.
ksaimouli
  • ksaimouli
oka
ksaimouli
  • ksaimouli
|dw:1360893431147:dw|
ksaimouli
  • ksaimouli
step 1 is that right
hartnn
  • hartnn
yes.
ksaimouli
  • ksaimouli
okay step 2|dw:1360893564991:dw|
hartnn
  • hartnn
what about the lower limit of 0, will that come later ?
hartnn
  • hartnn
so, you got pi^2/8-1/4 only by substituting upper limit ?
hartnn
  • hartnn
thats correct by the way, but incomplete
ksaimouli
  • ksaimouli
shut i forgot that literally i thought no value in polynomials but their is a value for trig
ksaimouli
  • ksaimouli
ya i found the mistake thx
hartnn
  • hartnn
yes, cos 0 is not 0
hartnn
  • hartnn
welcome ^_^

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