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ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ x^2 }{ 2 }\cos2x+\frac{ x }{ 2 }\sin2x+\frac{ 1 }{ 4 }\cos 2x\]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
to dw:1360893059171:dw
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
i tried this i got \[\frac{ \pi^2 }{ 8 }\frac{ 1 }{ 4 }\]
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
how u got that ? show your work, i'll spot the error.
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1360893431147:dw
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
step 1 is that right
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
okay step 2dw:1360893564991:dw
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
what about the lower limit of 0, will that come later ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so, you got pi^2/81/4 only by substituting upper limit ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
thats correct by the way, but incomplete
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
shut i forgot that literally i thought no value in polynomials but their is a value for trig
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
ya i found the mistake thx
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes, cos 0 is not 0
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
welcome ^_^
 one year ago
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