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ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ dy }{ dx }=x^2e^{4x}\]
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
solve the differential equation
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
i tried using by parts
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
i think that just means find the anti derivative of \(x^2e^{4x}\)and my guess is use parts twice
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
ya i used
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
but not solved let me show
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
i will use 7 technique
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1360895129811:dw
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1360895181802:dw
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1360895191642:dw
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
i think you have it backwards you want to drop the power on the \(x^2\) term
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
and now i should choose x^3 and e^4x
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
no the gimmick is to reduce the power, not raise it. raising the power makes it worse
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
\(u=x^2, dv = e^{4x}dx, du = 2x, v =\frac{1}{4}e^{4x}\)
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
okay i can do it this way so something wrong in my technique right
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
yes. as you can see your method just gave higher and higher powers of \(x\) you want to make them lower and lower
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
so instead of integrating id i take derivative
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
but if i follow the LIPET rule it says u= log right
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
i forget exactly how that box method works, but it is \[\int u dv =uv\int v du\]
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.2
make \(u=x^2, du = 2xdx, dv = e^{4x}dx, v =\frac{1}{4}e^{4x}\) get \[\int x^2e^{4x}=\frac{1}{4}e^{4x}x^2\frac{1}{2}\int e^{4x}xdx\] then do it again
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
okay got u
 one year ago
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