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ksaimouli
 3 years ago
solve
ksaimouli
 3 years ago
solve

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ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ dy }{ dx }=x^2e^{4x}\]

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0solve the differential equation

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0i tried using by parts

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i think that just means find the anti derivative of \(x^2e^{4x}\)and my guess is use parts twice

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0but not solved let me show

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0i will use 7 technique

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360895129811:dw

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360895181802:dw

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360895191642:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i think you have it backwards you want to drop the power on the \(x^2\) term

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0and now i should choose x^3 and e^4x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no the gimmick is to reduce the power, not raise it. raising the power makes it worse

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\(u=x^2, dv = e^{4x}dx, du = 2x, v =\frac{1}{4}e^{4x}\)

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0okay i can do it this way so something wrong in my technique right

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes. as you can see your method just gave higher and higher powers of \(x\) you want to make them lower and lower

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0so instead of integrating id i take derivative

ksaimouli
 3 years ago
Best ResponseYou've already chosen the best response.0but if i follow the LIPET rule it says u= log right

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i forget exactly how that box method works, but it is \[\int u dv =uv\int v du\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0make \(u=x^2, du = 2xdx, dv = e^{4x}dx, v =\frac{1}{4}e^{4x}\) get \[\int x^2e^{4x}=\frac{1}{4}e^{4x}x^2\frac{1}{2}\int e^{4x}xdx\] then do it again
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