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dietrich_harmon
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In circle O, CD = 44, OM = 20, ON = 19,CD l OM, EF l ON (The figure is not drawn to scale.)
 one year ago
 one year ago
dietrich_harmon Group Title
In circle O, CD = 44, OM = 20, ON = 19,CD l OM, EF l ON (The figure is not drawn to scale.)
 one year ago
 one year ago

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dietrich_harmon Group TitleBest ResponseYou've already chosen the best response.0
a.Find the radius. If your answer is not an integer, express it in radical form. b.Find FN. If your answer is not an integer, express it in radical form. c.Find EF. Express it as a decimal rounded to the nearest tenth.
 one year ago

dietrich_harmon Group TitleBest ResponseYou've already chosen the best response.0
@jim_thompson5910
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
dw:1360903051401:dw
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
dw:1360903107022:dw
 one year ago

dietrich_harmon Group TitleBest ResponseYou've already chosen the best response.0
i hate geometry..lol
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
dw:1360903151843:dw solve for x to find the radius a^2 + b^2 = c^2 20^2 + 22^2 = x^2
 one year ago

dietrich_harmon Group TitleBest ResponseYou've already chosen the best response.0
is this the answer
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
tell me what you get for x
 one year ago

dietrich_harmon Group TitleBest ResponseYou've already chosen the best response.0
42?
 one year ago

dietrich_harmon Group TitleBest ResponseYou've already chosen the best response.0
oops 22
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
20^2 + 22^2 = x^2 400 + 484 = x^2 x^2 = 884 x = ???
 one year ago

dietrich_harmon Group TitleBest ResponseYou've already chosen the best response.0
52
 one year ago

dietrich_harmon Group TitleBest ResponseYou've already chosen the best response.0
i don't know
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
x^2 = 884 x = sqrt(884) x = 2*sqrt(221)
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
so thats your radius
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
now you can use this radius to find EF and FN
 one year ago

dietrich_harmon Group TitleBest ResponseYou've already chosen the best response.0
202 + 222
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
solve for y y^2 + 19^2 = (2*sqrt(221))^2 y^2 + 381 = 884 keep going
 one year ago

d_loparsaie Group TitleBest ResponseYou've already chosen the best response.1
What do you do after you solve for y? @jim_thompson5910
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
I let y = EN so to find EF, you need to find 2y this is because EF = 2*EN EF = 2y
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
also, FN = EN, so once you get EN, you have found FN
 one year ago

d_loparsaie Group TitleBest ResponseYou've already chosen the best response.1
y^2 + 361=884?? y^2=523 right?
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
oh somehow I had 381...hmm lol yeah it's 361
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
y^2=523 y=sqrt(523)
 one year ago

d_loparsaie Group TitleBest ResponseYou've already chosen the best response.1
How did you get 884 up there?
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
(2*sqrt(221))^2 = 4*221 = 884
 one year ago

d_loparsaie Group TitleBest ResponseYou've already chosen the best response.1
alright so y=29.73?
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
leave it in radical form
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
unless it asks about the approximation and rounding it
 one year ago

d_loparsaie Group TitleBest ResponseYou've already chosen the best response.1
to leave it in radical form do I just leave it as y=sqrt(523)?
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
yes square roots are considered radicals
 one year ago

d_loparsaie Group TitleBest ResponseYou've already chosen the best response.1
Solving for y solves for both FN and EF..?
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
FN yes since FN = EN
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
but you have to double it to find EF
 one year ago

d_loparsaie Group TitleBest ResponseYou've already chosen the best response.1
So the one we just solved (y) is FN right? and I add FN and EN together.. but how do I do that since its in radical form?
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
or you can double FN to get EF
 one year ago

d_loparsaie Group TitleBest ResponseYou've already chosen the best response.1
1,046? right
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
no EF = 2*sqrt(523)
 one year ago

d_loparsaie Group TitleBest ResponseYou've already chosen the best response.1
How do I double Fn to get Ef
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
I just did it
 one year ago

d_loparsaie Group TitleBest ResponseYou've already chosen the best response.1
___ if 2*sqrt(523) is EF then half of that is Fn and En right..
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
correct
 one year ago

d_loparsaie Group TitleBest ResponseYou've already chosen the best response.1
Alright lol sorry I was confused on which was which. How do I find out what half of the radical is? just divide 523 by 2?
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
it's just 2*sqrt(523) and sqrt(523)
 one year ago

d_loparsaie Group TitleBest ResponseYou've already chosen the best response.1
EF=2*sqrt(523) and EN and FN = sqrt(523) .. wow haha I feel stupid. Thank you so much though!
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
it's fine, yw
 one year ago

d_loparsaie Group TitleBest ResponseYou've already chosen the best response.1
to find 2*sqrt(523) as a decimal rounded to the nearest tenth I multiply 523*2 and then take the square root of that number right?
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
you first take the square root of 523, then you double that result
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
then you round to whatever they want
 one year ago

d_loparsaie Group TitleBest ResponseYou've already chosen the best response.1
so the answer would be 45.74?
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
yep 2*sqrt(523) = 45.74 roughly
 one year ago

d_loparsaie Group TitleBest ResponseYou've already chosen the best response.1
Thank you again
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
sure thing
 one year ago
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