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anonymous
 3 years ago
In circle O, CD = 44, OM = 20, ON = 19,CD l OM, EF l ON (The figure is not drawn to scale.)
anonymous
 3 years ago
In circle O, CD = 44, OM = 20, ON = 19,CD l OM, EF l ON (The figure is not drawn to scale.)

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0a.Find the radius. If your answer is not an integer, express it in radical form. b.Find FN. If your answer is not an integer, express it in radical form. c.Find EF. Express it as a decimal rounded to the nearest tenth.

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1360903051401:dw

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1360903107022:dw

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1360903151843:dw solve for x to find the radius a^2 + b^2 = c^2 20^2 + 22^2 = x^2

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1tell me what you get for x

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.120^2 + 22^2 = x^2 400 + 484 = x^2 x^2 = 884 x = ???

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1x^2 = 884 x = sqrt(884) x = 2*sqrt(221)

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1so thats your radius

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1now you can use this radius to find EF and FN

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1solve for y y^2 + 19^2 = (2*sqrt(221))^2 y^2 + 381 = 884 keep going

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What do you do after you solve for y? @jim_thompson5910

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1I let y = EN so to find EF, you need to find 2y this is because EF = 2*EN EF = 2y

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1also, FN = EN, so once you get EN, you have found FN

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0y^2 + 361=884?? y^2=523 right?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1oh somehow I had 381...hmm lol yeah it's 361

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1y^2=523 y=sqrt(523)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0How did you get 884 up there?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1(2*sqrt(221))^2 = 4*221 = 884

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1leave it in radical form

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1unless it asks about the approximation and rounding it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0to leave it in radical form do I just leave it as y=sqrt(523)?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1yes square roots are considered radicals

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Solving for y solves for both FN and EF..?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1FN yes since FN = EN

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1but you have to double it to find EF

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So the one we just solved (y) is FN right? and I add FN and EN together.. but how do I do that since its in radical form?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1or you can double FN to get EF

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1no EF = 2*sqrt(523)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0How do I double Fn to get Ef

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0___ if 2*sqrt(523) is EF then half of that is Fn and En right..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Alright lol sorry I was confused on which was which. How do I find out what half of the radical is? just divide 523 by 2?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1it's just 2*sqrt(523) and sqrt(523)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0EF=2*sqrt(523) and EN and FN = sqrt(523) .. wow haha I feel stupid. Thank you so much though!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0to find 2*sqrt(523) as a decimal rounded to the nearest tenth I multiply 523*2 and then take the square root of that number right?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1you first take the square root of 523, then you double that result

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1then you round to whatever they want

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so the answer would be 45.74?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1yep 2*sqrt(523) = 45.74 roughly
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