• anonymous
  • Stacey Warren - Expert
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
  • katieb
I got my questions answered at in under 10 minutes. Go to now for free help!
  • whpalmer4
For problem s, you can see if you do a little bit of work that the two sides are the same length, and the sum of the squares of their lengths is the square of the length of the hypotenuse. Therefore the answer choice involving the Pythagorean theorem is correct. Here's how I worked it out: The two sides both go 7 in one direction and 1 in the other, so we can find the length by the Pythagorean theorem: \(d = \sqrt{7^2 + 1^2} = \sqrt{50} = 5\sqrt{2}\) The hypotenuse goes 8 units in one direction and 6 in the other, so its length is:\[d=\sqrt{8^2+6^2} = \sqrt{100} = 10\] We can see that these lengths satisfy the Pythagorean theorem: \((5\sqrt{2})^2 + (5\sqrt{2})^2 = 25*2 + 25*2 = 50+50 = 10^2 = 100\) So, this is a right triangle (and an isosceles one, at that).
  • whpalmer4
In #9 in file h, remember the memory aid: SOH CAH TOA Sin = Opposite over Hypotenuse Cos = Adjacent over Hypotenuse Tan = Opposite over Adjacent
  • whpalmer4
You'll have to give it your best shot...

Looking for something else?

Not the answer you are looking for? Search for more explanations.