Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

whpalmer4Best ResponseYou've already chosen the best response.0
For problem s, you can see if you do a little bit of work that the two sides are the same length, and the sum of the squares of their lengths is the square of the length of the hypotenuse. Therefore the answer choice involving the Pythagorean theorem is correct. Here's how I worked it out: The two sides both go 7 in one direction and 1 in the other, so we can find the length by the Pythagorean theorem: \(d = \sqrt{7^2 + 1^2} = \sqrt{50} = 5\sqrt{2}\) The hypotenuse goes 8 units in one direction and 6 in the other, so its length is:\[d=\sqrt{8^2+6^2} = \sqrt{100} = 10\] We can see that these lengths satisfy the Pythagorean theorem: \((5\sqrt{2})^2 + (5\sqrt{2})^2 = 25*2 + 25*2 = 50+50 = 10^2 = 100\) So, this is a right triangle (and an isosceles one, at that).
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.0
In #9 in file h, remember the memory aid: SOH CAH TOA Sin = Opposite over Hypotenuse Cos = Adjacent over Hypotenuse Tan = Opposite over Adjacent
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.0
You'll have to give it your best shot...
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.