## AonZ 2 years ago Halp please. Medal will be awarded Express in terms of log 2 (3) and log 2 (5) log 2 (1/6sqrt2)

1. AonZ

can you just check my work please @hartnn

2. AonZ

|dw:1360922596470:dw|

3. AonZ

correct so far?

4. hartnn

you got the 1st and second term correct. whats your 3rd term ? check/try it again

5. AonZ

my 3rd term is supposed to be sqrt 2. How else should i write it? all i can think of is 2 to the power of a half

6. hartnn

yes, first step, $$\log_2 (1/ 6\sqrt2)= \log_2 1- \log_2(6\sqrt 2)$$ i think you are clear on this step. now for $$\log_2(6\sqrt2)$$ use $$\log ab=\log a+\log b$$

7. AonZ

log 2(6) + log 2(2^1/2)

8. hartnn

correct, so far you have, $$\log_21-(\log_26+\log_22^{1/2})$$ now take the term, $$\log_2 2^{1/2}=...?$$

9. hartnn

Also, log of 1 in any base = 0 because a^0 =1

10. AonZ

yea so it will be 1/2

11. AonZ

well the 3rd term

12. AonZ

so -log2(6) - 1/2? :D

13. hartnn

correct, so are you clear till here : $$0-(\log 6+1/2)$$ now how can you write 6 as ?

14. hartnn

yes, but its still needs to simplify

15. AonZ

oh you can write 6 as -(log2(3) + log2(2) +1/2) -(log2(3) + 3/2)

16. AonZ

-log2(3) - 3/2 :D

17. hartnn

very good! $$\huge \color{red}{\checkmark }$$

18. AonZ

19. AonZ

hehe mine sucks lol

20. AonZ

copy and paste doesnt work :(

21. hartnn

do one thing, right click on that tick, select 'Show Math As' and then "Tex Commands" and then copy that code. :)

22. hartnn

or copy this : \huge \color{red}{\checkmark } and write it in between $ and $

23. hartnn

you can change the color if you want :)

24. AonZ

$\huge \color{purple}{\checkmark }$$\huge \color{purple}{\checkmark }$$\huge \color{purple}{\checkmark }$

25. AonZ

Thanks :D

26. hartnn

nice :) welcome ^_^