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AonZ Group TitleBest ResponseYou've already chosen the best response.1
Simplify \[\huge 5^{x+\log_{5}x }\]
 one year ago

AonZ Group TitleBest ResponseYou've already chosen the best response.1
i understand there is the rule how log 5 cancels out right?
 one year ago

AonZ Group TitleBest ResponseYou've already chosen the best response.1
but i think the answer would be x^x would it not?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
first step, use \(\huge a^{b+c}=a^b \times a^c\)
 one year ago

AonZ Group TitleBest ResponseYou've already chosen the best response.1
OHHH. Wow you are the best teacher in the WORLD. You seem to know what to explain first :P Thanks :) Answer then is 5^x * x?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
\(\huge \color {green}\checkmark\)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
welcome ^_^
 one year ago

AonZ Group TitleBest ResponseYou've already chosen the best response.1
im just taking a wild guess but is the a formula that is... \[\huge a^{b/c}=a^b  a^c \]
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
nopes, theres no such formula. \(\huge a^{(b/c)}= \sqrt[c]{a^b}\)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
a^ba^c cannot be further simplified.
 one year ago

AonZ Group TitleBest ResponseYou've already chosen the best response.1
yep somehow you know thats the exact formula i was looking for :D
 one year ago
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