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Simplify
\[\huge 5^{x+\log_{5}x }\]

i understand there is the rule how log 5 cancels out right?

but i think the answer would be x^x would it not?

first step, use
\(\huge a^{b+c}=a^b \times a^c\)

\(\huge \color {green}\checkmark\)

welcome ^_^

im just taking a wild guess but is the a formula that is...
\[\huge a^{b/c}=a^b - a^c \]

nopes, theres no such formula.
\(\huge a^{(b/c)}= \sqrt[c]{a^b}\)

a^b-a^c cannot be further simplified.

yep somehow you know thats the exact formula i was looking for :D

:)