AonZ
@hartnn This is just a question im bit confused with



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AonZ
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Simplify
\[\huge 5^{x+\log_{5}x }\]

AonZ
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i understand there is the rule how log 5 cancels out right?

AonZ
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but i think the answer would be x^x would it not?

hartnn
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first step, use
\(\huge a^{b+c}=a^b \times a^c\)

AonZ
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OHHH. Wow you are the best teacher in the WORLD. You seem to know what to explain first :P
Thanks :)
Answer then is 5^x * x?

hartnn
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\(\huge \color {green}\checkmark\)

hartnn
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welcome ^_^

AonZ
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im just taking a wild guess but is the a formula that is...
\[\huge a^{b/c}=a^b  a^c \]

hartnn
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nopes, theres no such formula.
\(\huge a^{(b/c)}= \sqrt[c]{a^b}\)

hartnn
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a^ba^c cannot be further simplified.

AonZ
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yep somehow you know thats the exact formula i was looking for :D

hartnn
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:)