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AonZ

  • 2 years ago

@hartnn This is just a question im bit confused with

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  1. AonZ
    • 2 years ago
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    Simplify \[\huge 5^{x+\log_{5}x }\]

  2. AonZ
    • 2 years ago
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    i understand there is the rule how log 5 cancels out right?

  3. AonZ
    • 2 years ago
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    but i think the answer would be x^x would it not?

  4. hartnn
    • 2 years ago
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    first step, use \(\huge a^{b+c}=a^b \times a^c\)

  5. AonZ
    • 2 years ago
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    OHHH. Wow you are the best teacher in the WORLD. You seem to know what to explain first :P Thanks :) Answer then is 5^x * x?

  6. hartnn
    • 2 years ago
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    \(\huge \color {green}\checkmark\)

  7. hartnn
    • 2 years ago
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    welcome ^_^

  8. AonZ
    • 2 years ago
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    im just taking a wild guess but is the a formula that is... \[\huge a^{b/c}=a^b - a^c \]

  9. hartnn
    • 2 years ago
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    nopes, theres no such formula. \(\huge a^{(b/c)}= \sqrt[c]{a^b}\)

  10. hartnn
    • 2 years ago
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    a^b-a^c cannot be further simplified.

  11. AonZ
    • 2 years ago
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    yep somehow you know thats the exact formula i was looking for :D

  12. hartnn
    • 2 years ago
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    :)

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