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 one year ago
Log question. Is there a rule that can solve this?
\[\huge \log_{\frac{ 1 }{ a }} \frac{ 1 }{ n }\]
 one year ago
Log question. Is there a rule that can solve this? \[\huge \log_{\frac{ 1 }{ a }} \frac{ 1 }{ n }\]

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AonZ
 one year ago
Best ResponseYou've already chosen the best response.0@agent0smith can you help with this?

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.1Yeah i'm not sure what you want to do with it... you can change it into a couple of different forms?

yakzo
 one year ago
Best ResponseYou've already chosen the best response.0There is a formula for changing the base of the logarithm.

AonZ
 one year ago
Best ResponseYou've already chosen the best response.0well il type full equation prove log a(x) = log 1/2 (x)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2use : \(\huge \log_ab=\dfrac{\log b}{\log a}\)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2u sure, this is the Q ? prove log a(x) = log 1/2 (x)

AonZ
 one year ago
Best ResponseYou've already chosen the best response.0wait my bad LOL log a(x) = log 1/a (x)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2right, use the property i gave on RIGHT side.

AonZ
 one year ago
Best ResponseYou've already chosen the best response.0dw:1360928591721:dw these cancel right?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2simplify both numerator and denominator. and  log x = log(1/x) was unnecessary and no, not directly.

AonZ
 one year ago
Best ResponseYou've already chosen the best response.0how else do i do it then??

AonZ
 one year ago
Best ResponseYou've already chosen the best response.0oh so the negatives cancel?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2yesh, now negatives can cancel.

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2again apply that property on what you have...

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2\(\huge \dfrac{\log b}{\log a}=\log_ab\)

AonZ
 one year ago
Best ResponseYou've already chosen the best response.0yes i can see how the equal each other now :)

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.1\[\log_{a} x = \log_{\frac{ 1 }{ a }} x\] Use the log rule on the right side \[\log_{\frac{ 1 }{ a }} x = \frac{ \log_{a} x }{ \log_{a} \frac{ 1 }{ a } } = \frac{ \log_{a} x }{ \log_{a} a ^{1}}= \frac{ \log_{a} x }{ \log_{a} a} = \frac{ \log_{a} x }{1}\]

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.1moved the negatives, makes it easier to follow. \[\log_{\frac{ 1 }{ a }} x = \frac{  \log_{a} x }{ \log_{a} \frac{ 1 }{ a } } = \frac{ \log_{a} x }{ \log_{a} a ^{1}}= \frac{ \log_{a} x }{ \log_{a} a} = \frac{ \log_{a} x }{1}\]

AonZ
 one year ago
Best ResponseYou've already chosen the best response.0ahh ok thanks to all of you :)
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