A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
AonZ
 2 years ago
Last question!!!
log 1/5 (25)
AonZ
 2 years ago
Last question!!! log 1/5 (25)

This Question is Closed

AonZ
 2 years ago
Best ResponseYou've already chosen the best response.0check the identity by evaluating...

AonZ
 2 years ago
Best ResponseYou've already chosen the best response.0\[\huge \log_{\frac{ 1 }{ 5 }}25 \]

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1use the same property i gave for last Q

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1\(\frac{1}{5} = 5^{1}\). What would you multiply to that to get \(5^2\)?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1yes, simplify numerator and denominator separately.

agent0smith
 2 years ago
Best ResponseYou've already chosen the best response.2\[\large \log_{\frac{ 1 }{ 5 }} 5 = \frac{ \log_{5} 25 }{ \log_{5}\frac{ 1 }{ 5}} = \frac{ \log_{5} 5^2 }{ \log_{5} 5^{1}}\]

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1Just figure out what you multiply to \(5^{1}\) to get \(5^2.\)

AonZ
 2 years ago
Best ResponseYou've already chosen the best response.0ahh @agent0smith explained it pretty good :)

AonZ
 2 years ago
Best ResponseYou've already chosen the best response.0@agent0smith How did you get the base to be 5? Like all of them?

agent0smith
 2 years ago
Best ResponseYou've already chosen the best response.2Not sure what you mean... I just used base 5 because it makes it easy to solve.

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1@AonZ Change of bases.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1you can choose any base for using that property,e,5,10,... thats why its unspecified in the property

AonZ
 2 years ago
Best ResponseYou've already chosen the best response.0so if you use change of base rule you can choose ANY base?

AonZ
 2 years ago
Best ResponseYou've already chosen the best response.0wow i reckon i understand logs a lot better now :P

agent0smith
 2 years ago
Best ResponseYou've already chosen the best response.2^ correct @ParthKohli shouldn't it be "figure out what power you need to raise 5^1 to, to get 25" as opposed to "Just figure out what you multiply to 5^−1 to get 5^2"?

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1But you get the point.

agent0smith
 2 years ago
Best ResponseYou've already chosen the best response.2Ah okay, cos i was wondering how this helps:\[5^{1} \times 5^3 = 25\]compared to this \[(5^{1})^{2}=25\]

agent0smith
 2 years ago
Best ResponseYou've already chosen the best response.2@AonZ you could also do it this way (but it makes it a bit more difficult): \[ \large \log_{\frac{ 1 }{ 5 }} 5 = \frac{ \log_{25} 25 }{ \log_{25}\frac{ 1 }{ 5}} = \frac{1 }{ \log_{25} 25^{0.5}}\]

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1or simply \(\huge \log_{\frac{ 1 }{ 5 }} 5 = \frac{ \log_{} 5 }{ \log_{}\frac{ 1 }{ 5}} \)

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1Much better up there.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1\(\huge \log_{\frac{ 1 }{ 5 }} 25 = \frac{ \log_{} 25 }{ \log_{}\frac{ 1 }{ 5}}\)

agent0smith
 2 years ago
Best ResponseYou've already chosen the best response.2^ that works fine, but requires a calculator.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1\(\huge \log_{\frac{ 1 }{ 5 }} 25 = \frac{ \log_{} 25 }{ \log_{}\frac{ 1 }{ 5}}= \frac{ \log_{} 5^2 }{ \log_{}\frac{ 1 }{ 5}}\)

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1\[\dfrac{\log _5 5^2}{\log _5 5^{1}} = \]

agent0smith
 2 years ago
Best ResponseYou've already chosen the best response.2I'm assuming @hartnn is using base 10...

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1does not matter what base i use, by default its 10

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.1You can use change of base too.

agent0smith
 2 years ago
Best ResponseYou've already chosen the best response.2\[ \frac{ \log_{} 25 }{ \log_{}\frac{ 1 }{ 5}} \] I mean, how are you solving this w/o changing base again, or using a calculator?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1\(\huge \log_{\frac{ 1 }{ 5 }} 25 = \frac{ \log_{} 25 }{ \log_{}\frac{ 1 }{ 5}}= \frac{ \log_{} 5^2 }{ \log_{}\frac{ 1 }{ 5}}=\dfrac{2 \log 5}{1 \log 5}=2\)

agent0smith
 2 years ago
Best ResponseYou've already chosen the best response.2Oh you're simplifying to \[ \frac{ \log_{} 25 }{ \log_{}\frac{ 1 }{ 5}} = \frac{ 2 \log5 }{ \log5 }\]
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.