## DHASHNI 2 years ago At a fair i bought 6 erasers and 2 pens for \$15. If i could have bought 4 more erasers for \$14 than pens for \$9, the price of a pen was????

1. DHASHNI

@AriPotta @HELP!!!! @Austin_Rain @Aperez @asianfever @hba

2. DHASHNI

@alewis98 @BlackChickSwag @chance327 @DLS @evergirl

3. AriPotta

i don't understand the last part of your question. is it saying 4 erasers cost \$14??

4. DHASHNI

thats the problem its an aptitude question

5. kelliegirl33

Is it saying 4 more erasers (plus the ones she bought) which would make it 10 erasers = \$ 14 ???

6. DHASHNI

i am not able to understand the ques

7. DHASHNI

@damien @e.cociuba @firefightere9 @gjhfdfg @Hayatcakes @HB0315

8. kelliegirl33

6e + 2p = 14 I am sorry...I can't get past this :(

9. DHASHNI

it's ok

10. DHASHNI

@Mimi_x3 @myko @n14r96

11. AriPotta

the question's worded weird

12. kelliegirl33

yes it is....confusing

13. DHASHNI

thank u ppl jus got the answer by my own

14. AriPotta

cool. can you tell us the answer?

15. AriPotta

just curious

16. DHASHNI

hmm.. yea

17. DHASHNI

the ques says that 6 erasers and 2 pens is for \$15 so let us consider the cost of eraser and pen be E and P respectively => 6E+2P = 15 then , it says 4 more erasers for \$14 than pens for \$9 that is , if the number of pens is 'n' then the number of erasers is '(4+n)' nP=9 ,(4+n)E=14