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boomerang285

  • one year ago

Please help with this sigma problem, i think the answer is 10!!

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  1. boomerang285
    • one year ago
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    \[\sum_{1}^{3} (3i+1)\]

  2. boomerang285
    • one year ago
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    and I also have this one which is \[\sum_{1}^{2} 3i\]

  3. boomerang285
    • one year ago
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    which i think is 6???

  4. hjhancock
    • one year ago
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    the 1 on the bottom is giving you your starting place and the 3 on the top is telling you how many times to go through it so for the first on, you have (3*1+1)+(3*2+1)+(3*3+1)

  5. boomerang285
    • one year ago
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    oooohhh so its 21, that makes total sense, and I also see what I was doing wrong...

  6. boomerang285
    • one year ago
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    so would the answer to the second one then be 9 instead of 6?

  7. hjhancock
    • one year ago
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    yeah, because you iterate twice(the 2 on the top) so its (3*1)+(3*2)

  8. boomerang285
    • one year ago
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    gotcha, thank you so much!

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