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dfresenius Group TitleBest ResponseYou've already chosen the best response.0
dw:1360952276270:dw
 one year ago

dfresenius Group TitleBest ResponseYou've already chosen the best response.0
should i do a u sub or change cos2x identity?
 one year ago

JamesJ Group TitleBest ResponseYou've already chosen the best response.2
Well, cos(2x) = cos^2 x  sin^2 x = 1  2sin^2 x, hence \[ \sqrt{1  \cos 2x} = \sqrt{1  (1  2\sin^2 x)} \] which can be nicely simplified.
 one year ago

dfresenius Group TitleBest ResponseYou've already chosen the best response.0
my answer is wrong
 one year ago

JamesJ Group TitleBest ResponseYou've already chosen the best response.2
What does this expression simplify to? \[ \sqrt{1  \cos 2x} = \sqrt{1  (1  2\sin^2 x)} \]
 one year ago

JamesJ Group TitleBest ResponseYou've already chosen the best response.2
\[ \sqrt{1  (1  2\sin^2 x)} = \sqrt{2\sin^2 x} = ... \]
 one year ago

dfresenius Group TitleBest ResponseYou've already chosen the best response.0
dw:1360954273501:dw
 one year ago

JamesJ Group TitleBest ResponseYou've already chosen the best response.2
\[ \sqrt{1  (1  2\sin^2 x)} = \sqrt{2\sin^2 x} = \sqrt{2} \sin x \] provided sin x > 0. Hence \[ \int \sqrt{1  \cos 2x} \ dx \ = \ \int \sqrt{2} \sin x \ dx \ = \ ... \]
 one year ago

dfresenius Group TitleBest ResponseYou've already chosen the best response.0
sqrt(2)cosx
 one year ago

dfresenius Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt(2)cosx\]
 one year ago

dfresenius Group TitleBest ResponseYou've already chosen the best response.0
from 0 to pi, the book asnwer says its 2sqrt2
 one year ago

dfresenius Group TitleBest ResponseYou've already chosen the best response.0
i get 0
 one year ago

JamesJ Group TitleBest ResponseYou've already chosen the best response.2
What is cos(pi) = ...? And cos(0) = ... ?
 one year ago

dfresenius Group TitleBest ResponseYou've already chosen the best response.0
1 and 1
 one year ago

dfresenius Group TitleBest ResponseYou've already chosen the best response.0
sqrt(2) + sqrt(2) oh ya 2sqrt 2
 one year ago

dfresenius Group TitleBest ResponseYou've already chosen the best response.0
sorry for wasting your time :(
 one year ago
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