anonymous
  • anonymous
Trig integrals. sqrt(1-cos2x)dx
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1360952276270:dw|
anonymous
  • anonymous
should i do a u sub or change cos2x identity?
JamesJ
  • JamesJ
Well, cos(2x) = cos^2 x - sin^2 x = 1 - 2sin^2 x, hence \[ \sqrt{1 - \cos 2x} = \sqrt{1 - (1 - 2\sin^2 x)} \] which can be nicely simplified.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
my answer is wrong
JamesJ
  • JamesJ
What does this expression simplify to? \[ \sqrt{1 - \cos 2x} = \sqrt{1 - (1 - 2\sin^2 x)} \]
JamesJ
  • JamesJ
\[ \sqrt{1 - (1 - 2\sin^2 x)} = \sqrt{2\sin^2 x} = ... \]
anonymous
  • anonymous
|dw:1360954273501:dw|
JamesJ
  • JamesJ
\[ \sqrt{1 - (1 - 2\sin^2 x)} = \sqrt{2\sin^2 x} = \sqrt{2} \sin x \] provided sin x > 0. Hence \[ \int \sqrt{1 - \cos 2x} \ dx \ = \ \int \sqrt{2} \sin x \ dx \ = \ ... \]
anonymous
  • anonymous
sqrt(2)-cosx
anonymous
  • anonymous
\[-\sqrt(2)cosx\]
JamesJ
  • JamesJ
+ C, yes
anonymous
  • anonymous
from 0 to pi, the book asnwer says its 2sqrt2
anonymous
  • anonymous
i get 0
JamesJ
  • JamesJ
What is cos(pi) = ...? And cos(0) = ... ?
anonymous
  • anonymous
-1 and 1
anonymous
  • anonymous
sqrt(2) + sqrt(2) oh ya 2sqrt 2
anonymous
  • anonymous
sorry for wasting your time :(
JamesJ
  • JamesJ
np

Looking for something else?

Not the answer you are looking for? Search for more explanations.