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dfreseniusBest ResponseYou've already chosen the best response.0
dw:1360952276270:dw
 one year ago

dfreseniusBest ResponseYou've already chosen the best response.0
should i do a u sub or change cos2x identity?
 one year ago

JamesJBest ResponseYou've already chosen the best response.2
Well, cos(2x) = cos^2 x  sin^2 x = 1  2sin^2 x, hence \[ \sqrt{1  \cos 2x} = \sqrt{1  (1  2\sin^2 x)} \] which can be nicely simplified.
 one year ago

JamesJBest ResponseYou've already chosen the best response.2
What does this expression simplify to? \[ \sqrt{1  \cos 2x} = \sqrt{1  (1  2\sin^2 x)} \]
 one year ago

JamesJBest ResponseYou've already chosen the best response.2
\[ \sqrt{1  (1  2\sin^2 x)} = \sqrt{2\sin^2 x} = ... \]
 one year ago

dfreseniusBest ResponseYou've already chosen the best response.0
dw:1360954273501:dw
 one year ago

JamesJBest ResponseYou've already chosen the best response.2
\[ \sqrt{1  (1  2\sin^2 x)} = \sqrt{2\sin^2 x} = \sqrt{2} \sin x \] provided sin x > 0. Hence \[ \int \sqrt{1  \cos 2x} \ dx \ = \ \int \sqrt{2} \sin x \ dx \ = \ ... \]
 one year ago

dfreseniusBest ResponseYou've already chosen the best response.0
from 0 to pi, the book asnwer says its 2sqrt2
 one year ago

JamesJBest ResponseYou've already chosen the best response.2
What is cos(pi) = ...? And cos(0) = ... ?
 one year ago

dfreseniusBest ResponseYou've already chosen the best response.0
sqrt(2) + sqrt(2) oh ya 2sqrt 2
 one year ago

dfreseniusBest ResponseYou've already chosen the best response.0
sorry for wasting your time :(
 one year ago
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