A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Factor 2x4  20x2  78.
2(x2 3)(x2 13) *****
2(x2+ 3)(x2 13)
2(x2 3)(x2+ 13)
I think is right ****
anonymous
 3 years ago
Factor 2x4  20x2  78. 2(x2 3)(x2 13) ***** 2(x2+ 3)(x2 13) 2(x2 3)(x2+ 13) I think is right ****

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0help me @FibonacciChick666

FibonacciChick666
 3 years ago
Best ResponseYou've already chosen the best response.1I would like you to please first try and check your answer before I try the problem. You are going to do this by using the FOIL method.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I did that's y I asked if its right

FibonacciChick666
 3 years ago
Best ResponseYou've already chosen the best response.1alrighty good, I'm working on it right now

FibonacciChick666
 3 years ago
Best ResponseYou've already chosen the best response.1ok so only one of your answers is correct. let's go through the process together.

rosedewittbukater
 3 years ago
Best ResponseYou've already chosen the best response.0First factor out the 2 to get 2(x^410x^239) Replace any x^2 value with the variable a, so x^4 becomes a^2 because x^2 squared is x^4. You just do this to take the place of any x^2 s to make it easier, if that makes sense. So 2(a^210a39). Then you can do regular factoring. 3 and 13 multiply to become 39, and 313=10. So The equation would become \[2(a+13)(a3)\] Then change the a's back into x^2. So the answer is \[2(x ^{2}+3)(x ^{2}13)\] So the answer is the second one.

FibonacciChick666
 3 years ago
Best ResponseYou've already chosen the best response.1So the first thing that we want to do is pull out any like terms. What does each term in the expression have in common?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay I need help again

FibonacciChick666
 3 years ago
Best ResponseYou've already chosen the best response.1ok, does the term (78) contain an \[x ^{2}\]

rosedewittbukater
 3 years ago
Best ResponseYou've already chosen the best response.0You can check your work by multiplying the factors back together using either the box method or FOIL. \[2(x ^{4}13x ^{2}+3x ^{2}39)\]Combine like terms to get \[2(x ^{4}10x ^{2}39)\]Then distribute the 2 \[2x ^{4}20x ^{2}78\]You know your answer is correct if it is the same as the original equation.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0will u help me in another problem @rosedewittbukater

FibonacciChick666
 3 years ago
Best ResponseYou've already chosen the best response.1let's try a different approach. can you divide 78 by x^2 without leaving a remainder?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay I posted it already

FibonacciChick666
 3 years ago
Best ResponseYou've already chosen the best response.1ok so what is 78 divided by x^2 ?

rosedewittbukater
 3 years ago
Best ResponseYou've already chosen the best response.0Where did you post it

FibonacciChick666
 3 years ago
Best ResponseYou've already chosen the best response.139 is 78 divided by only 2 but think about the other terms listed do they also divide by 2?

rosedewittbukater
 3 years ago
Best ResponseYou've already chosen the best response.0She's trying to ask what number or value can be divided out of every single part of the equation. There's no x^2 in 78 so the only common number that all of the numbers can be divided by is 2.

FibonacciChick666
 3 years ago
Best ResponseYou've already chosen the best response.1let's try a slightly simplified example if you have the equation: \[2x+2\] What number is common to both terms?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.