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Shannon20150
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Factor completely.
m4  n4
(m2 n2)(m + n)(m  n) ****
(m2+ n2)(m + n)(m  n)
(m2+ n2)(m  n)2
I think it is *******
 one year ago
 one year ago
Shannon20150 Group Title
Factor completely. m4  n4 (m2 n2)(m + n)(m  n) **** (m2+ n2)(m + n)(m  n) (m2+ n2)(m  n)2 I think it is *******
 one year ago
 one year ago

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rosedewittbukater Group TitleBest ResponseYou've already chosen the best response.0
It would be the second one. m^4n^4 could factor to become (m^2+n^2)(m^2n^2). To further factor it, you change (m^2n^2) to (m+n)(mn). So the answer is (m^2+n^2)(m+n)(mn). Then check your work First multiply the last two to become m^2nm+nmn^2, which simplifies to m^2n^2. Then multiply that by (m^2+n^2) which would be \[m ^{4}+m^2n^2m^2n^2+n^4\] Which can be simplified by combining like terms to \[m^4+n^4\]The answer is the second one.
 one year ago
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