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charliem07
find the real zeros of the given polynomial and their corresponding multiplicities. Use this information along with a sign chart to provide a rough sketch of the graph of the polynomial. Compare your answer with the result from a graphing utility. a(x)=x(x+2)2
the first x is odd so the equation intersects at the o and the other one is at -2
The function is a(x)=x(x+2)². If you have to find the zeros, you have to solve x(x+2)²=0. What are the solutions?
|dw:1360963879772:dw|
@ZeHanz the leading term is x^3
x^3=infiniti x^3=-infiniti
The zeros are -2 and 0. Because of the multiplicity (2) of -2, there is no sign change if you pass -2. If the leading term is x^3, there is a sign change when you pass 0. I think you already did well!
Compare with this Geogebra plot: