Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

find the real zeros of the given polynomial and their corresponding multiplicities. Use this information along with a sign chart to provide a rough sketch of the graph of the polynomial. Compare your answer with the result from a graphing utility. a(x)=x(x+2)2

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
the first x is odd so the equation intersects at the o and the other one is at -2
The function is a(x)=x(x+2)². If you have to find the zeros, you have to solve x(x+2)²=0. What are the solutions?
|dw:1360963879772:dw|

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

@ZeHanz the leading term is x^3
x^3=infiniti x^3=-infiniti
The zeros are -2 and 0. Because of the multiplicity (2) of -2, there is no sign change if you pass -2. If the leading term is x^3, there is a sign change when you pass 0. I think you already did well!
Compare with this Geogebra plot:
1 Attachment

Not the answer you are looking for?

Search for more explanations.

Ask your own question