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charliem07
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find the real zeros of the given polynomial and their corresponding multiplicities. Use this information along with a sign chart to provide a rough sketch of the graph of the polynomial. Compare your answer with the result from a graphing utility.
a(x)=x(x+2)2
 one year ago
 one year ago
charliem07 Group Title
find the real zeros of the given polynomial and their corresponding multiplicities. Use this information along with a sign chart to provide a rough sketch of the graph of the polynomial. Compare your answer with the result from a graphing utility. a(x)=x(x+2)2
 one year ago
 one year ago

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charliem07 Group TitleBest ResponseYou've already chosen the best response.0
the first x is odd so the equation intersects at the o and the other one is at 2
 one year ago

ZeHanz Group TitleBest ResponseYou've already chosen the best response.1
The function is a(x)=x(x+2)². If you have to find the zeros, you have to solve x(x+2)²=0. What are the solutions?
 one year ago

charliem07 Group TitleBest ResponseYou've already chosen the best response.0
dw:1360963879772:dw
 one year ago

charliem07 Group TitleBest ResponseYou've already chosen the best response.0
@ZeHanz the leading term is x^3
 one year ago

charliem07 Group TitleBest ResponseYou've already chosen the best response.0
x^3=infiniti x^3=infiniti
 one year ago

ZeHanz Group TitleBest ResponseYou've already chosen the best response.1
The zeros are 2 and 0. Because of the multiplicity (2) of 2, there is no sign change if you pass 2. If the leading term is x^3, there is a sign change when you pass 0. I think you already did well!
 one year ago

ZeHanz Group TitleBest ResponseYou've already chosen the best response.1
Compare with this Geogebra plot:
 one year ago
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